A $2.03*g$ mass of calcium salts contains $1.33*g$ calcium carbonate. What is the $%$ calcium carbonate; and what is the percentage by mass of of calcium in calcium carbonate?

Md Ariful Islam

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Md Ariful Islam

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So we have the $"%calcium carbonate, "m/m$. We are not finished yet, because we have to address the percentage by mass of calcium metal in calcium carbonate:

$%Ca=(40.08*g*mol^-1)/(100.09*g*mol^-1)=40%$ with respect to calcium carbonate.

And thus the $%Ca$ IN THE SAMPLE

$=(1.33*g)/(2.03*g)xx(40.08*g*mol^-1)/(100.09*g*mol^-1)xx100%=26.2%$

We have assumed that ALL of the calcium metal is present as the carbonate.

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