- The balanced chemical equation
- The molar mass of $"CaCO"_3$
- The molar ratio of $"CaO"$ to $"CaCO"_3$
- The molar mass of $"CaO"$
Your strategy has four steps:
- Write the balanced chemical equation.
- Use the molar mass of $"CaCO"_3$ to calculate the moles of $"CaCO"_3$.
- Use the molar ratio of $"CaO"$ to $"CaCO"_3$ from the equation to calculate the moles of $"CaO"$.
- Use the molar mass of $"CaO"$ to calculate the mass of $"CaO"$.
Your answer should be about 2.6 kg of $"CaO"$.