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This reaction is commonly used to illustrate basic solubility rules, and solubility equilibria.

All nitrates are soluble, hence silver nitrate is soluble; and all halides are soluble, EXCEPT for $AgX$, $PbX_2$, and $Hg_2X_2$.

Thus silver nitrate is soluble, but silver chloride precipitates from solution as a curdy white solid.

We write the net ionic equation as:

$Ag^(+) + X^(-) rarr AgX(s)darr$

Silver chloride is a curdy white solid; silver bromide is a creamy yellow; and silver iodide is bright yellow. (On standing the silver halides tend to reduce to silver metal, and the precipitates darken.)

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