First write balanced chemical equation for this ion-exchange reaction : $K_3PO_4+Al(NO_3)_3->3KNO_3+AlPO_4$. This balanced chemical equation represents ratio in which the chemicals combine and form products. So clearly 1 mole of...
1 Answers 1 views$n = (200*g)/(241.86*g*mol^-1)$ $~=$ $0.80*mol$ $Fe(NO_3)_3$. How many moles of $O$, and $N$ does the given mass represent?
1 Answers 1 viewsNumber of nitrate ions $"Moles of Mg"("NO"_3)_2 = 1.00 × 10^"-6" color(red)(cancel(color(black)("g Mg"("NO"_3)_2))) × ("1 mol Mg"("NO"_3)_2)/(148.31 color(red)(cancel(color(black)("g Mg"("NO"_3)_2)))) = 6.743 × 10^"-9"color(white)(l) "mol Mg"("NO"_3)_2$ $"Moles of NO"_3^"-" = 6.743...
1 Answers 1 views$"Moles of sodium chloride"$ $(581*cancelg)/(58.44*cancelg*mol^-1)$ $=$ $"approx. "10*mol$ Thus $10$ $mol$ sodium metal are required.
1 Answers 1 viewsPb(NO3)2- Lead Nitrate NaI - Sodium Iodide $Pb(NO_3)_2 + 2NaI --> PbI_2+ 2NaNO_3$ Moles of Lead(II) Nitrate = $mass // molar mass$ = 25.0 grams//(207.20 xx 1 + 14.01 xx...
1 Answers 1 viewsThionyl chloride reacts quantitatively (and violently) with water as represented by the following reaction: $SOCl_2(l) + 2H_2O(l) rarr SO_2(g)uarr + 2HCl(aq)+Delta$ $"Moles of thionyl chloride"=(35.0*g)/(118.97*g*mol^-1)=0.294*mol.$ And CLEARLY, thionyl chloride is...
1 Answers 1 viewsThis appears to be a limiting reactant problem. 1. Write the balanced equation $"2NaCN" + "H"_2"SO"_4 → "Na"_2"SO"_4 + "2HCN"$ 2. Calculate the moles of $"Na"_2"SO"_4$ formed from...
1 Answers 1 viewsYou need to start by writing the balanced chemical equation that describes the of sodium chloride $color(red)(2)"Na"_ ((s)) + "Cl"_ (2(g)) -> 2"NaCl"_ ((s))$ The balanced chemical...
1 Answers 1 viewsFirst start by finding the mass of the gas mixture. $density = (mass )/ (volume)$ $mass = density xx volume$ $mass = 19.92 \ g/L xx 5.00 \ L$ $mass...
1 Answers 1 views$"mass percent"="grams of solute"/"grams of solution"xx100"$ The mass in grams of a mass % solution, is the sum of the mass in grams of the and the mass in grams...
1 Answers 1 views