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At standard temperature and pressure (0 ∘C and 1.00 atm ), 1.00 mol of an ideal gas occupies a volume of 22.4 L. What volume would the same amount of gas occupy at the same pressure and 95 ∘C ?

Md Ariful Islam

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Md Ariful Islam

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P1 = P2 = 1.00 atm = constant;

V1 = 22.4 L;

T1 = 0 °C = 273.15 K;

T2 = 95 °C = 368.15 K;

V2 = unknown;

Solution:

(P1×V1)/(T1) = (P2×V2)/(T2);

P1 = P2 = constant;

(V1)/(T1) = (V2)/(T2);

V2 = (V1×T2)/(T1);

V2 = (22.4 L × 368.15 K)/(273.15 K) = 30.19 L;

Answer: 30.19 L

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