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A sample of N2 has 1.70 moles and occupies 3.80 l at 25.0˚C.
A) What volume will it occupy with 2.60 moles?
B) How many moles are in a sample that occupies 1.45 L?
According to the ideal gas law: pV=nRT p ndash; pressure (atm) V ndash; volume (L) n ndash; amount (moles) R ndash; universal gas constant T ndash; temperature (K) P, R,...
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a cylinder of helium gas has a volume of 1.0 L. The gas in the cylinder exerts a pressure of 800 kPa at 30 degrees. What volume would this gas occupy at SATP
SATP - Standard Ambient Temperature and Pressure.SATP: T = 25∘C and P = 1 bar.P1 = 800 kPa;V1 = 1.0 L;T1 = 30∘C = 303 K;P2 = 1 bar = 100 kPa;V2...
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a ballon filled with helium gas at 1.00atm occupies 11.9L. what volume would the volume occupy in the upper atmosphere, at a pressure of 0.17atm and a constant temperature?
The equation states that product of pressure and volume is a constant for a given mass of confined gas as long as the temperature is constant. For comparing the same...
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A sample of oxygen occupies a volume of 250. mL at a pressure of 704. torr. What volume will the gas occupy at a pressure of 800. torr if temerature is held constant
P1×V1= P2×V2 V2 = P1×V1/P2 V2 = 704×250/800 = 220. ml Answer: 220. ml.
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At standard temperature and pressure (0 ∘C and 1.00 bar), 1.00 mol of an ideal gas occupies a volume of 22.7 L. What volume would the same amount of gas occupy at the same pressure and 30 ∘C ?
t(0)=0 С T=273 K p=1.00 bar V=22.7 l N=1 mol t(1)=30 С T=303 K Find V=? According to the Boyle-Mariotte law P(0) V(0)/T(0) = const If p=const V(0)/T(0)= V(1)/T(1) V(1)=V(0)T(1)/T(0)=22.7...
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A gas sample is held at constant pressure. The gas occupies 3.62 L of volume when the temperature is 21.6°C. Determine the temperature at which the volume of the gas is 3.42 L
5.32 C
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At standard temperature and pressure (0 ∘C and 1.00 atm ), 1.00 mol of an ideal gas occupies a volume of 22.4 L. What volume would the same amount of gas occupy at the same pressure and 95 ∘C ?
P1 = P2 = 1.00 atm = constant;V1 = 22.4 L;T1 = 0 °C = 273.15 K;T2 = 95 °C = 368.15 K;V2 = unknown;Solution:(P1×V1)/(T1) = (P2×V2)/(T2);P1 = P2 =...
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A helium balloon occupies 112mL at 90.0 kPa and 34 degrees Celsius. What volume would it occupy at standard temperature and pressure (101.3 kPa 0.00 degrees Celsius)
Use the combined gas law.P1V1/T1 = P2V2/T290*0.112/307 = 101.3*V2/2730.0328 = 0.3711*V2V2 = 0.088L
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A student collects 25.0 mL of gas at 96.0 kPa. What volume would this gas
occupy at 101.325 kPa. There is no change in temperature or mass.
According to Boyle's law (P1V1 = P2V2, T=const) it is possible to calculate volume of gas after changing of pressure:25.0 mL * 96.0 kPa = 101.325 kPa * V2V2 =...
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A mass of gas occupies 1.00 L at 100 kPa. At what pressure does this gas
occupy
a) 2.00 litres,
b) 0.500 litres?
P1 = 100 kPaV1 = 1.00 LSolution:The relationship for Boyle’s Law can be expressed as follows: P1V1 = P2V2, where P1 and V1 are the initial pressure and volume values,...
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