At standard temperature and pressure (0 ∘C and 1.00 bar), 1.00 mol of an ideal gas occupies a volume of 22.7 L. What volume would the same amount of gas occupy at the same pressure and 30 ∘C ?

Md Ariful Islam

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t(0)=0 С T=273 K p=1.00 bar V=22.7 l N=1 mol t(1)=30 С T=303 K Find V=? According to the Boyle-Mariotte law P(0) V(0)/T(0) = const If p=const V(0)/T(0)= V(1)/T(1) V(1)=V(0)T(1)/T(0)=22.7 *303/273=25.19 l
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