A gas sample occupies a volume of 15.0 L at 30 ^oC and 750 torr. At what temperature will this gas occupy a volume of 25.0 L at the same pressure?

d,e

pH= -log[H+]pH= -log[1×10^-3]pH= 32) pH= -log[3.6×10^-5]pH= 5-log3.6pH= 4.44

a) 4x3

In this question, temperature, T does not change (is constant) hence only pressure, P and volume, V changes.In that case we apply Boyle's Law, P1V1=P2V2P1=1240 torrentP2=730 torrentV1=47.2 LV2 = P1V1/P2...

147N+42He→178O+11H714N+24He→817O+11H is an example of a fission reaction

Energy (n), angular momentum (ℓ), magnetic moment (mℓ), and spin (ms).

1 cubic metre =1000 litres10l = 1×10/1000 = 0.01B. 0.01m3

Solution:q = m × C × ΔTq = m × C × (Tf - Ti),where:q = amount of heat energy gained or lost by substancem = mass of sampleC = specific heat...

V1/T1 =V2/T20.06 m3 / 313 K = V2 / 328 KV2 = 0.063 m3 = 63 cm3

 volume V1 =12.0 L temperature T1 = 25°C = 273 K and Pressure = 750 torr.new volume V2 =15.0 L at 750 torrtemperature T2 = ?combined gas law saysV1/T1 = V2/T2T2 =...