A given amount of oxygen gas has a volume of 25.0 L at a temperature of 37oC and a pressure of 1.0 atm. At what temperature would this gas occupy a volume of 22.0 L at a pressure of 1.0 atm?

Dalton's law states; The total pressure exerted by a mixture of gases is equal to the sum of the pressures of each of the different gases making up the mixture,...

3.0atm — 5dm^36atm — xx=5dm^3*6atm/3atm=10gm^3

Using the gas law: pV = nRT, and keeping the same number of moles of gas (n),we find the final volume V2:V2 = (T2/p2)*(p1*V1/T1) = (293 K/ 4.0 atm)*(2.0 atm...

Standart conditions: Temperature 273.15 K Pressure 101.325 kPa Using the universal gas law: pV = nRT or pV = mRT/M hence, m(O2) = pVM/RT where p - pressure V -...

SATP - Standard Ambient Temperature and Pressure.SATP: T = 25∘C and P = 1 bar.P1 = 800 kPa;V1 = 1.0 L;T1 = 30∘C = 303 K;P2 = 1 bar = 100 kPa;V2...

P1 = 3.0 atmV1 = 5 dm3P2 = (3.0 * 2) = 6.0 atmV2 = unknownT1 = T2 = 301 K = const Solution:Since the temperature and amount of gas remain...

Solution:The molar mass of NH3 is 17.03 g/molThe molar mass of O2 is 32.00 g/molCalculate the moles of each gas:a) (5.8 g NH3) × (1 mol NH3 / 17.03 g...

P = 2 atmV = unknownn = 2.0 molR = 0.082 atm dm3 K-1 mol-1T = -133°C = 140 КSolution:The Ideal Gas equation can be used: PV = nRTTo find...

P1×V1= P2×V2 V2 = P1×V1/P2 V2 = 704×250/800 = 220. ml Answer: 220. ml.

t(0)=0 С T=273 K p=1.00 bar V=22.7 l N=1 mol t(1)=30 С T=303 K Find V=? According to the Boyle-Mariotte law P(0) V(0)/T(0) = const If p=const V(0)/T(0)= V(1)/T(1) V(1)=V(0)T(1)/T(0)=22.7...