A gas filled a 5 dm<sup>3 </sup>container at a pressure of 3.0 atm, at 301 K. If the pressure of the system is doubled, what is the new volume that the gas will occupy at 301 K?

Md Ariful Islam

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Md Ariful Islam

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P1 = 3.0 atm

V1 = 5 dm3

P2 = (3.0 * 2) = 6.0 atm

V2 = unknown

T1 = T2 = 301 K = const

 

Solution:

Since the temperature and amount of gas remain unchanged, Boyle's law can be used. 

Boyle's gas law can be expressed as: P1V1 = P2V2

To find the new volume, solve the equation for V2:

V2 = P1V1 / P2

V2 = (3.0 atm × 5 dm3) / (6.0 atm) = 2.5 dm3

V2 = 2.5 dm3

Answer: 2.5 dm3 is the new volume if gas.

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