STP states that at STP the pressure is 1atm and the temperature is 273K.Therefore V2= (P1V1T2)/T1P2V2 = (3×250×273)/(290×1)V2 = 706 L
1 Answers 1 viewsVolume =1.005dm3
1 Answers 1 viewsP1V1/T1 =P2v2/T21 × 800/273= 0.9504 × 1000/T22.9304 = 950.4/T22.9304 T2 = 950.4T2 = 324.324KT2 = 51.32°C
1 Answers 1 views1,44L
1 Answers 1 viewsp1 = 0,06 atm = 6079,5Pa V1 = 1100ml = 0,0011m3 T1 = 780C = 351 K p2 = 1,31 atm = 132735,8Pa T2 = 440C = 317 K V2...
1 Answers 1 viewsV = 90,6 ml
1 Answers 1 viewsP1 = P2 = 1.00 atm = constant;V1 = 22.4 L;T1 = 0 °C = 273.15 K;T2 = 95 °C = 368.15 K;V2 = unknown;Solution:(P1×V1)/(T1) = (P2×V2)/(T2);P1 = P2 =...
1 Answers 1 viewsDue to ideal gas law:pV/T = constp1V1/T1 = p2V2/T2p2 = (p1*V1*T2)/(T1*V2) = 10 atm
1 Answers 1 viewspV=nRT;p=nRT/V=8.25*10^(-2) * 8.314 * 388/0.255 =1043.65 Pa= 0.01 atmAnswer: 0.01 atm
1 Answers 1 viewsLet P1,V1 be the initial pressure,voloume and temparature of the gas at T1=273.15 and P2,V2 be the final pressure,voloume of tha gas T2 is the final temparature.Use the combined gas law:P1V1/T1...
1 Answers 1 views