If a solution containing 41.98g of mercury(II) perchlorate is allowed to react completely with a solution containing 6.256g of sodium sulfide, how many grams of solid precipitate will form?

Grams of 40% solution of hydrochloride acid needed =37.4g

110 g/cc is larger than the density of iridium. Certainly you meant 1.10 g/cc. To ease the calculations, take 1 liter of the solution. Its mass is m = V*D...

98-90= 88×8×1.8= 115.2450/115.2= 3.91

n(Cl2) = 8.3 molesSolution:Sodium + chlorine = sodium chloride.The equation of a chemical reaction:2Na + Cl2 = 2NaClAccording to the chemical equation: n(Na)/2 = n(Cl2) = n(NaCl)/2.Therefore,n(NaCl) = 2*n(Cl2) =...

The dry weight in the clay sample equals:mdry = mtotal - mmoisturewhere mdry - dry weight, mtotal - total weight, mmoisture - wet weightAs mmoisture = mtotal × 20.50 %...

Pb(NO3)2 + 2NaI = 2NaNO3 + PbI2n = m / MM (Pb(NO3)2) = 331.2 g/molM (NaI) = 150 g/molM (NaNO3) = 85 g/moln (Pb(NO3)2) = 25 / 331.2 = 0.08...

Solution:(Hg = 200, O=16, 1 mole = 6.02×1023)Balanced chemical equation:2HgO(s) ⟶ 2Hg(l) + O2(g)Calculate the moles of HgO:The molar mass of HgO is (200 + 16) = 216 g/molHence,(4.3 g...

CuS + NaNO3 → Cu(NO3)2 + Na2S – no reaction! This reaction between these substances is not possible, because copper II sulfide not dissociates into ions in water, and probable...

The 60.0 g of mercury is 82.6% of mercuric sulfide, than the mass of all mercuric sulfide is 100%. The mass of mercuric sulfide (g) = (60.0g/82.6%)*100% = 72.6 g....

It is not clear with what substance HCL is allowed to react. However, from the common knowledge H2 will be formed upon reaction of HCl with metals, for example Mg...