Mercuric sulfide, HgS, contains 82.6% mercury by mass. What mass of mercuric sulfide can be prepared from 60.0 g of mercury?

Volume =31.32mL

In this reaction, mercury is product.

400 μmol = 400x10-6 mol = 400x10-3 mmol = 0.4 mmol c=n/V V=n/c V=(0.4 mmol)/(9.8×〖10〗^(-9) mmol/L)=4.1×〖10〗^7 L

Solution:(Hg = 200, O=16, 1 mole = 6.02×1023)Balanced chemical equation:2HgO(s) ⟶ 2Hg(l) + O2(g)Calculate the moles of HgO:The molar mass of HgO is (200 + 16) = 216 g/molHence,(4.3 g...

V = m / ρ V (Hg) = 34500 g / 13.6 g/ml = 2536,8 ml = 2537 ml Answer: 2537 ml

CuS + NaNO3 → Cu(NO3)2 + Na2S – no reaction! This reaction between these substances is not possible, because copper II sulfide not dissociates into ions in water, and probable...

2Co(s)+3HgCl2(aq)→2CoCl3(aq)+3Hg(l) n (Hg) = n (HgCl2) n = m/M M (Hg) = 200.59 g/mol M (HgCl2) = 271.5 g/mol n (Hg)=4.41/200.59 = 0.02 mol m (HgCl2) = n (HgCl2) ·...

86.6/201:13.4/32=1:1.PbS.Pb+S=PbS.(10.5/201) x 32= 1.67164179 g of S

128.2 mole x mole2K + S -> K2S2 mole 1 molen(K) = m(K)/M(K) = 5 000 g/39 g/mole = 128.2 mole128.2 mole/2 mole = x mole/1 molex = (128.2 *...

Balanced equation : 2Co + 3HgCl2 → 2CoCl3 + 3Hg3 moles of mercuric chloride = 3 moles of Hg3 ( 271.6g) mercurial chloride = 3 (200.6)g Hg1g Hg= 3 × 271.6 /(3×200.6)g mercuric chloride 5.81g Hg...