Find the molarity and molality of a 15% solution of sulphuric acid whose density is 110g/cc and the molar mass of the sulphuric acid is 98g/mol

Md Ariful Islam

0 like 0 dislike
1 views
Share with your friends

1 Answers

Md Ariful Islam

Call
110 g/cc is larger than the density of iridium. Certainly you meant 1.10 g/cc. To ease the calculations, take 1 liter of the solution. Its mass is m = V*D = 1000*1.10 = 1100 g = 1.10 kg The mass of sulfuric acid is m(acid) = m(solution)*w(acid) = 1100*0.15 = 165 g m(water) = m(solution) - m(acid) = 935 g The molarity is defined as the number of moles of the solute per liter of the solution. The molality is defined as the number of moles of the solute per kilogram of the solvent. To obtain the molarity and molality of the solution we need the number of moles of acid: n(H2SO4) = m(H2SO4)/M(H2SO4) = 1.684 mol Hence we can obtain the molarity and molality: c(H2SO4) = n(H2SO4)/V(solution) = 1.68 mol/l mu;(H2SO4) = n(H2SO4)/m(water) = 1.684/0.935 = 1.80 mol/kg
0 like 0 dislike
1 views
Talk Doctor Online in Bissoy App
an excess of copper(II) oxide is reacted with 1.0 mol dm3 sulphuric acid. Calculate the volume of sulphuric acid needed to prepare 20.0 g of copper(II) sulphate.

For the reaction of cupric oxide with sulfuric acid, the balanced chemical equation is CuO plus H₂SO₄ react to form CuSO₄ plus H₂O.

1 Answers 1 views
A 95.5 grams of sodium sulfate (Na₂SO₄)is dissolved in 1150 grams of distilled H2O. Calculate the molality of the Na₂SO₄ solution. Molar mass: Na = 23 g/mol ; S = 32 g/mol ; O = 16 g/mol

Molar mass of Na2SO4= 142.04 g/mol95.5/142.04= 0.6720.672mol/1.15kg= 0.585mol/Kg

1 Answers 1 views
The commercial sulphuric acid solution includes 96.4 % H2SO4 by mass. The density of the solution is 1.84 g/mL. Calculate the molarity of the sulphuric acid solution?

Molecular weight of H2SO4 is 98.079 g-mol.1 ml equals 1.84 g. Hence, 96.4ml equals 96 x 1.84 = 177.376g.Therefore, 100 ml volume contains 177.376 g H2SO4. So 1 liter contains...

1 Answers 1 views
The density at 20 0 C of a 0.500 M solution of acetic acid in water is 1.0042 g/mL. What is the molality of the solution? The molar mass of acetic acid, CH3CO2H, is 60.05 g/mol.

Let the volume of the acetic acid solution be 1 litre = 1000 mlthus, moles of acetic acid = molarity*volume of solution in litres = 0.5*1 = 0.5 molesnow, molar...

1 Answers 1 views
Concentrated sulphuric acid is a solution that has a density of 1.84g/ml and contains 98.3% H2SO4 by mass.what is the molarity of this acid

Molarity =18.4M

1 Answers 1 views
3.75M sulfuric acid solution that has a density of 1.23g/ml. Calculate the mass percent,molality and normality of sulfuric acid?H=1g/mol , O=16g/mol , S=32 g/mol

Solution:sulfuric acid = H2SO4The molar mass of H2SO4 = 2×Ar(H) + Ar(S) + 4×Ar(O) = 2×1 + 32 + 4×16 = 98 (g/mol).Suppose that the volume of the solution is...

1 Answers 1 views
Sulphuric acid has a molecular mass of 98 and a density of 1.94 g/mL. You are given a 10% v/v solution of sulphuric acid. What is its molar concentration? Give your answer to 2 decimal places.

If we have 1L of solution, then we have 100 ml (0.1L = 10% from 1L) of sulphuric acid in it. Find the mass of 100 ml of sulphuric acid:...

1 Answers 1 views
100g of calcium chloride is dissolved in 1L of aqueous solution. Assume solution density of 1.07g/mL. Calculate the molarity, molality, and percent mass of the solution.

n(CaCl2)=m/M=100/111=0.9molemolarity=n(CaCl2)/V(solution)=0.9/1=0.9mole/liter=0.9Mmolality=n(CaCl2)/m(solvent)=0.9/(1·1000·1.07)=8,4·10^-4 mole/gPercent mass=m(CaCl2)/m(solution)=100/(1070+100)=0.085=8.5%

1 Answers 1 views
If a solution containing 41.98g of mercury(II) perchlorate is allowed to react completely with a solution containing 6.256g of sodium sulfide, how many grams of solid precipitate will form?

Hg(ClO4)2 + Na2S = HgS + 2NaClO4n(Hg(ClO4)2)= 41.98g/399.49g/mol = 0.105 moln(Na2S) = 6.256g/78g/mol = 0.08 molHg(ClO4)2 in the excess, Na2S reacts completely. n(HgS) = 0.08 molm(HgS) = 0.08mol*232.66g/mol = 18.6...

1 Answers 1 views
The pH value of a sulphuric acid is 2. What is the molarity of this sulphuric acid? (Show me steps please)

H2SO4 <=> 2H+ + SO42- ;pH=-lg[H+] ;[H+]=10^(-pH)=10-2=0.01;[H2SO4]=[H+]/2=0.01/2=0.005 mol/L;Answer: the molarity of sulphuric acid is 0.005 M;

1 Answers 1 views
X