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How many grams of 5% barium hydroxide solution will be needed to react 2 moles of sulfur (IV) oxide?
Molar Mass of barium hydroxide = 171.34g/mol5% of barium hydroxide = 8.567 g/molSulfur IV oxide Molar Mass = 64.066g/mol2 moles of sulfur IV oxide = 128.066g/molX×(1mol/128.066) × (2/1) = 2moles...
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Find the number of grams of zinc metal that will completely react with 730 grams of hydrochloride acid to produce zinc chloride and hydrogen gas
Quantity of Zinc metal ;=362g
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Using the chemical equation: B2H6 + 3O2 -> 2HBO2 + 2H2O. How many grams of HBO2 are needed to react completely with 42.7 grams of O2?
Grams of HBO2=14.23g
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How many moles of barium metal react to produce 0.100mol of barium nitride? Hpw many moles of nitrogren gas react?
Ba(s) + N2(g) -> Ba3N2(s)
x y 0.100 3Ba(s) + 2N2(g) ------gt; Ba3N2(s) 3 2 1 x=3*0.100/1=0.300 mol y=2*0.100/2-0.200 mol
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How many grams of aluminum hydroxide are needed to react with 1.0 grams of hydrochloric acid?
The chemical equation for thi reaction is Al(OH)3 + 3HCl = AlCl3 + 3H2O MW (HCl) = MW (H) + MW (Cl) = 1.0 + 35.5 = 36.5 g/mol MW...
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if 27 grams of copper II sulfide reacts with 22 grams of sodum nitrate how many grams of sodium sulfide can be formed
CuS + NaNO3 → Cu(NO3)2 + Na2S – no reaction! This reaction between these substances is not possible, because copper II sulfide not dissociates into ions in water, and probable...
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How many grams of Barium metal are needed to produce 75 grams of barium sulfide in the following equation: Ba(s) + S8 (s) + BaS (s)
The chemical equation is 8Ba(s) + S8 (s) → 8BaS (s) Molar mass of Barium is M = 137.3 g/mol Molar mass of barium sulfide is M = 169.4 g/mol...
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how many moles of hydrogen are needed to completely react with 1.23 moles of nitrogen?
According to the reaction equation:N2+3H2=2NH3n(H2) = n(N2) *3 = 1.23 mol * 3 = 3.69 molAnswer: 3.69 mol
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If a solution containing 41.98g of mercury(II) perchlorate is allowed to react completely with a solution containing 6.256g of sodium sulfide, how many grams of solid precipitate will form?
Hg(ClO4)2 + Na2S = HgS + 2NaClO4n(Hg(ClO4)2)= 41.98g/399.49g/mol = 0.105 moln(Na2S) = 6.256g/78g/mol = 0.08 molHg(ClO4)2 in the excess, Na2S reacts completely. n(HgS) = 0.08 molm(HgS) = 0.08mol*232.66g/mol = 18.6...
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