How many grams of 5% barium hydroxide solution will be needed to react 2 moles of sulfur (IV) oxide?

Aqueousaluminum sulfate reacts with aqueous barium hydroxide, producing precipitates of aluminum hydroxide and barium sulfate: Al2(SO4)3 + 3Ba(OH)2 = 3BaSO4 + 2Al(OH)3

The reaction between aluminium chloride and sodium hydroxide can be written as following:AlCl3 + 3NaOH = Al(OH)3 + 3NaClAs 7.80 moles of aluminium hydroxide are produced, 7.80 moles of aluminium...

m = (4.2 mol)*(32 g/mol) = 134.4 g

x y 0.100 3Ba(s) + 2N2(g) ------gt; Ba3N2(s) 3 2 1 x=3*0.100/1=0.300 mol y=2*0.100/2-0.200 mol

Solution:Solid barium reacts with oxygen gas at a temperature of over 800°C to produce solid barium oxide.2Ba + O2 = 2BaO.

Solution:The balanced chemical equation:3Ca(OH)2 + 2H3PO4 → Ca3(PO4)2 + 6H2OAccording to the equation above: Moles of Ca(OH)2 / 3 = Moles of H2O / 6Moles of Ca(OH)2 = Moles of...

Solution:Balanced chemical equation:Ba(OH)2 + Li2SO4 → BaSO4 + 2LiOHAccording to the equation above: n(Ba(OH)2) = n(Li2SO4)C(Ba(OH)2) × V(Ba(OH)2) = C(Li2SO4) × V(Li2SO4)Divide to isolate C(Li2SO4):C(Li2SO4) = C(Ba(OH)2) × V(Ba(OH)2) /...

Ca(OH)2 + 2HNO3 = 2H2O + Ca(NO3)2 0.0900 mol HNO3 x (1 mol HNO3 / 1 mol Ca(OH)2) = 0.0900 mol Ca(OH)2

The chemical equation is 8Ba(s) + S8 (s) → 8BaS (s) Molar mass of Barium is M = 137.3 g/mol Molar mass of barium sulfide is M = 169.4 g/mol...

 xmol    0.0054molBa(OH)2 + 2HBr = BaBr2 +2H2O 1mol      2mol n(HBr) = C(HBr) × V(HBr) = 0.225M × 0.024L = 0.0054mol.n(Ba(OH)2) = x = 0.0054 × 1 / 2 mol = 0.0027mol.V(Ba(OH)2) = n(Ba(OH)2) /...