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Ammonia NH3 chemically reacts with oxygen gas O2 to produce nitric oxide NO and water H2O. What mass of water is produced by the reaction of 2.1g of oxygen gas?
5O2 + 4NH3 = 6H2O + 4NO5O2 = 6H2O5 × 32g O2 = 6 × 18g H2O1g O2 = 6×18/(5×32)g H2O2.1g O2 = 6×18×2.1/(5×32) g H2O= 1.42g H2O
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How many grams of 5% barium hydroxide solution will be needed to react 2 moles of sulfur (IV) oxide?
Molar Mass of barium hydroxide = 171.34g/mol5% of barium hydroxide = 8.567 g/molSulfur IV oxide Molar Mass = 64.066g/mol2 moles of sulfur IV oxide = 128.066g/molX×(1mol/128.066) × (2/1) = 2moles...
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BaO (s) + H2O (g) = Ba(OH)2 (s) If you want to completely react 10.25 g of barium oxide, how many grams of water will you need?
From the equation, the ratio of barium Oxide and water is 1:1Molar Mass of BaO = 153.3310.25/153.33 = 0.0668 molesMolar Mass of H2O = 18.015= 0.0668 × 18.015= 1.204g
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Zinc metal displaces oxygen from zinc(ii)oxide however it is unable to displace oxygen from magnesium oxide.Explain
1) Zinc metal displaces oxygen from zinc(ii)oxide:Zn + ZnO = ZnO + ZnThis reaction does not make sense.2) It is unable to displace oxygen from magnesium oxide:That is because Mg...
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how many litres of oxygen at STP react with 72 g of aluminum to produce aluminum oxide?
Litres =6.55L
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A magnesium ribbon weighing 1.25g formed 3.45 of oxide when made to react with oxygen.
What is the % of oxygen in the compound?
m(Mg) = 1.25g m(oxide) = 3.45g m(O) = m(oxide) -m(Mg) = 3.45 - 1.25 = 2.2 g w(O) = m(O)/m(oxide)*100% = 2.2/3.45*100% = 63.77%
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How many moles of barium metal react to produce 0.100mol of barium nitride? Hpw many moles of nitrogren gas react?
Ba(s) + N2(g) -> Ba3N2(s)
x y 0.100 3Ba(s) + 2N2(g) ------gt; Ba3N2(s) 3 2 1 x=3*0.100/1=0.300 mol y=2*0.100/2-0.200 mol
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In the reaction between aluminum and oxygen to form aluminum oxide, how many
grams of aluminum will react with 10.0 L of oxygen at 735 mm Hg and 10º C?
1) p = 735 mm Hg = 735 *133.322 = 97991.7 Pa; 2) V = 10L = 0.01 m3 ; 3) T = 10 °C = 283 K; 4) ν = 97991.7*0.01/8.314*283 = 0.42...
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Hydrogen gas and oxygen gas react to form liquid water in a closed container. How much oxygen is needed if 4.8 g of hydrogen produces 43.3 g of water?
43.3 - 4.8 = 38.5(g) oxygen
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What is the mass percent composition of manganese and oxygen in the oxide?
Given: 3.144g of manganese reacts with oxygen to produce 6.348g of manganese oxide.
3,144 gr 6,348 gr xMn + yO =˃ MnxOy 55x 55x +16y 3,144×(55x+16y)=6,348 × 55x 172,92 x + 50,304y = 349,14x 50,304y=176,22x y=3,5x x=2 y=7 Answer: Mn2O7
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