In the reaction between aluminum and oxygen to form aluminum oxide, how many grams of aluminum will react with 10.0 L of oxygen at 735 mm Hg and 10º C?

Grams of Aluminum metal can be produced=52.92g

Litres =6.55L

Grams of aluminum oxide produced =12.57g

Fe2O3(s) + 2Al(s) -----> 2Fe(s) +  Al2O3(s)The magnesium ribbon ignites the thermite starter mixture, which in turn ignites the thermite mixture. In an extremely exothermic reaction, the aluminum reduces the iron in the...

If 2Al2O3 --gt; 4Al+ 3O2; So, first of all we can find amount of substance of Al2O3: n(Al2O3) = m(Al2O3)/M(Al2O3); M(Al2O3) = Ar(Al)*2 + Ar(O) *3; M(Al2O3) = 27*2+16*3 =...

Aluminum oxide is decomposed using electricity toproduce aluminum metal by next reaction: 2Al2O3 ---gt; 4Al + 3O2 Now it is possible to calculate mass of aluminum metal: 100g Al2O3 *...

Given Moles of Mgo is 0.15 moles . Mg react with O2 and form MgO .2 mole of Mg gives 2 mole of Mgo .So 0.15 moles of Mg Gives...

Mass of aluminum oxide=34.7g

You can calculate this by such reaction: NH₄NO₃ --gt; N₂ + frac12;O₂ + 2H₂O ==gt; 2NH₄NO₃ --gt; 2N₂ + O₂ + 4H₂O The law of conservation of mass solves this...

2Al + 3O2→ 2Al2O3 m = 2*27*50.1/(3*22.4) =40.25 g where 2 mol is amount of aluminium which took part in the reaction according to the chemical equation; 27 g/mol is...