show that compounds N<sub>2</sub>O, NO, N<sub>2</sub>O<sub>3</sub>,NO<sub>2</sub> and N<sub>2</sub>O<sub>5</sub> illustrate the law of multiple proportions?

Md Ariful Islam

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Md Ariful Islam

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The law of multiple proportion displays that when 2 elements combine with each other forming 2 or more chemical compound then different amount of 1 element which react with definite amount of second element are in whole number ratios.

Therefore, we fix the mass of either O or N element theafter you find that the mass of second element is also get in the simplest whole number ratios and hence this law is illustrated.

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Fe<sub>2</sub>O<sub>3</sub>+3CaS = Fe<sub>2</sub>S<sub>3</sub>+3CaO How many grams of Fe<sub>2</sub>O<sub>3</sub> are needed to produce 51.9 grams of CaO?

Solution:Fe2O3 + 3CaS = Fe2S3 + 3CaOx g 51,9 g(Fe2O3) = 56*2+16*3= 160g/mol(CaO)=40+16=56g/molXmol(CaO)= 51,9/56= 0,96Xmol(Fe2O3)=0,92/3=0,308Xg(Fe2O3)=160*0,308/1=49,28Answer:m(Fe2O3)=49,28g

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What is the ΔH° for the following reaction (in kJ/mol)? 2 Na <sub>(s) </sub>+ 2 H<sub>2</sub>O<sub> (l)</sub> →<sub> </sub> 2 NaOH<sub> (aq) </sub>+ H<sub>2</sub> <sub>(g)</sub>

From the given info, we know the amount of heat released when 2 moles of Na is reacted. We're asked for the heat per 0.5 moles. So, (368.6 kJ/2mol)0.5000 mol = 92.15...

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N<sub>2(g)</sub>+3H<sub>2(g)</sub>-&gt;2NH<sub>3(g)</sub> Given:H<sub>2(g)</sub>=131G N<sub>2(g)</sub>=192 NH<sub>3(g)</sub>0=193. S<sup>0 </sup>values in J/K.mol

Value =199 J/K.mol

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How many mL of 0.250 M KOH will react with 15.0 mL of 0.350 M H<sub>2</sub>SO<sub>4</sub>? The reaction is : 2KOH + H<sub>2</sub>SO<sub>4</sub> → K<sub>2</sub>SO<sub>4</sub> + 2H<sub>2</sub>O

mL of 0.250 M KOH=5.5

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In the following reaction, how many liters of O<sub>2</sub> will produce 43.62 liters of CO<sub>2</sub> at STP? C<sub>3</sub>H<sub>8</sub> + 5 O<sub>2</sub> 3 CO<sub>2</sub> + 4 H<sub>2</sub>O

Litres of O2=72.7L O2

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How many moles of CO<sub>2</sub> will be produced when you burn 12.5 moles of C<sub>2</sub>H<sub>4</sub>? ( C<sub>2</sub>H<sub>4</sub> + 3 O<sub>2</sub> ---&gt; 2 CO<sub>2</sub> + 2 H<sub>2</sub>O )

Mole ratio C2H4:CO2=1:2= 12.5×2=25moles of CO2

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Can you please help me balance this equation?Na[sub]3[/sub]PO[sub]4[/sub] + Ba(NO[sub]3[/sub])[sub]2[/sub] = Ba[sub]3[/sub](PO[sub]4[/sub])[sub]2[/sub] + NaNO[sub]3[/sub]

The correct balanced equation is: Na3PO4 + Ba(NO3)2 = BaPO4 + Na3(NO3)2

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CH <sub>3 </sub>C(CH <sub>3 </sub>) <sub>2 </sub>CH <sub>2 </sub>CH=CHCH <sub>2 </sub>CH <sub>3 </sub>what is the correct IUPAC name

The correct IUPAC name is 6,6-dimethylhept-3-ene.

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Iron oxide formula Fe<sub>2</sub>O<sub>3 </sub>how many molecules of Fe<sub>3</sub>O<sub>3 </sub>there in (5x<sup>2</sup>) mol of Fe<sub>2</sub>O<sub>3</sub>, if x=4?

3.21 * 1025 molecules

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How many moles of ammonium sulfate can be made from the reaction of 30.0 moles of ammonia and sulfuric acid? NH<sub>3 </sub>+ H<sub>2</sub>SO<sub>4</sub> → (NH<sub>4</sub>)<sub>2</sub>SO<sub>4</sub>

Solution:Balanced chemical equation:2NH3 + H2SO4 → (NH4)2SO4According to the equation above: n[NH3]/2 = n[(NH4)2SO4]Therefore,n[(NH4)2SO4] = n[NH3] / 2 = 30.0 mol / 2 = 15.0 mol (NH4)2SO4Answer: 15.0 moles of ammonium sulfate can...

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