If an object has a density of $8.65$ $g$$/cm^3$, what is its density in units of $kg$$/m^3$?

Redshift and blueshift are phenomena that occur when an object is moving relative to an observer. It is called the Doppler effect. If an object moves towards an observer, it...

Let's break the answer down into three parts: $color (brown) ("First,"$ we're going to convert grams to pounds using this conversion factor: $color(white)(aaaaaaaaaaaaaaaaa$ 1 pound = 453.592 grams $color (purple)...

Mass is measured in $"kg"$, volume in $"m"^3$ and mass density in $"kg"$ $"m"^-3$. The formula for density is given by the following equation: $rho=m/V$ where $rho$ is the density,...

$rho, "density" ="Mass"/"Volume"$. The object displaces a volume of $(50-30)*mL =20*mL$. Given that we know the mass the calculation of the density is now easy.

By definition, $rho_"density"="Mass"/"Volume"$, and thus it typically has the units $g*mL^-1$; in this example your $7.5*g$ mass displaces a $5.0*mL$ of water, and thus........ $rho=(7.5*g)/((30.1-25.1)*mL)=1.50*g*mL^-1$.......

$"Density"$ is an $"intensive property"$, a property that depends on the nature of the material, unlike the $"extensive properties"$ such as mass and volume, which are determined by the extent...

We ASSUME that is displaces $1.75*L$ of water. And thus $rho=(12*kg)/(1.75*L)=6.86*kg*L^-1=6.86*g*mL^-1$. From where did I get the volume of the object?

Alright so we know the formula for is $rho=m/v$ => where $rho$ is the density with units of the derived components, $m$ is the mass, and $v$ is the volume....

In your example, $rho=("Mass")/("Volume")=(598*g)/(1.2*cancelLxx10^(3)*mL*cancel(L^-1))$ $=$ $0.498*g*mL^-1$. Is the solution likely to be aqueous? Why or why not?

First, let's find the volume of the spherical object. The formula for the volume of a sphere is: $Rightarrow V = frac(4)(3) pi r^(3)$ $Rightarrow V = frac(4)(3) cdot pi...