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How do you find the mass, volume, and density of an object, and what formulas and Sl units are used for each? Would equal volumes of two different substances have the same or different masses? Why?
Mass is measured in $"kg"$, volume in $"m"^3$ and mass density in $"kg"$ $"m"^-3$. The formula for density is given by the following equation: $rho=m/V$ where $rho$ is the density,...
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An irregularly shaped object that has a mass of 40 g is placed into a graduated cylinder filled with 30 mL of water. The object causes the water to displace to 50 mL. What is the density of the object?
$rho, "density" ="Mass"/"Volume"$. The object displaces a volume of $(50-30)*mL =20*mL$. Given that we know the mass the calculation of the density is now easy.
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A piece of meta ha a density of 11.3 g/cm^3 and a volume of 6.7 cm^3. What is the mass of this piece of metal?
$rho," density "=$ $"Mass"/"Volume"$. Thus $"Mass"$ $=$ $rhoxx"volume"$ $=$ $11.3*g*cancel(cm^-3)xx6.7*cancel(cm^3)$ $=$ $??*g*cm^3$.
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If a wooden block were cut into eight identical pieces, the density of each piece compared to the density of the original block would be?
$"Density"$ $=$ $"Unit mass"/"Unit volume"$. Given that most materials have uniform volume, and uniform mass, the quotient remains constant. In other words, $"density"$ is a so-called property.
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A rock sample has a mass of 16 grams and a volume of 8 cubic centimeters. When the rock is cut in half what is the volume and density of each piece?
$rho="Mass"/"Volume"=(16*g)/(8*cm^-3)$ $=$ $??*g*cm^-3$ And the volume of each piece is $??*cm^3$.
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A piece of wood that measures 3.0 cm by 6.0 cm by 4.0 cm has a mass of 80.0 grams. What the density of the wood? Would the piece of wood float in water?
The density of a substance can be calculated using: $d=m/V$ where $m$ is the mass, and $V$ is the volume. Here we do not have the volume given, however...
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A piece of metal that measures 33.0 cm by 46.0 cm by 48.0 cm has a mass of 800.0 grams. What is the density of the metal? Would the piece of metal float in water?
By definition, $rho_"metal"="mass of metal"/"volume of metal"$ $=(800*g)/(33.0*cmxx46.0*cmxx48.0*cm)=0.0659*g*cm^-3$ And this is an IMPROBABLY undense metal. The LEAST dense metal, lithium, is approx. $0.5*g*cm^-3$...(at any rate this metal reacts with water)...the...
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The density of an object is 10g/cm^3.what does this statement mean?
The statement is given as $"density" = "10 g/cm"^3$ In other words, it reads $10$ grams per cubic centimeter or alternatively $10$ grams per milliliter. This tells us...
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Lewis has a copper pipe with a length of 150 cm and a mass of 800 grams. He cuts a piece of the copper pipe with a length of 90 cm. How do you work out the mass of this piece of copper pipe?
I would consider the Linear of the pipe as: $delta="Linear Density"="mass"/"length"$ or: $delta=800/150=5.3g/(cm)$ When you cut it you are left with $90cm$ of pipe but with the same linear density...
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How many particle or molecules of $Na_2CO_3$ are produced when 10g of $NaOH$ is used? $22.3 x 10^24$ particles of $NaOH$ are needed to produce how many liters of $H_2O$? How many particles/molecules of $NaOH$ are from 30 gram of $NaOH$?
$2NaOH(s) + CO_2(g) -> Na_2CO_3(s) + H_2O(l)$ Molar mass of $NaOH = 40 $ $2xx40 g$ of $NaOH$ produces $6.02 xx 10^23$ molecules of $Na_2CO_3$ $:.$ $10 g$ of $NaOH$...
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