How many particle or molecules of $Na_2CO_3$ are produced when 10g of $NaOH$ is used? $22.3 x 10^24$ particles of $NaOH$ are needed to produce how many liters of $H_2O$? How many particles/molecules of $NaOH$ are from 30 gram of $NaOH$?

Md Ariful Islam

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Md Ariful Islam

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$2NaOH(s) + CO_2(g) -> Na_2CO_3(s) + H_2O(l)$

Molar mass of $NaOH = 40 $

$2xx40 g$ of $NaOH$ produces $6.02 xx 10^23$ molecules of $Na_2CO_3$
$:.$ $10 g$ of $NaOH$ produces $(6.02xx10^23xx10)/(2xx40)$ molecules of $Na_2CO_3$
$= 7.5 xx 10^22$ molecules of $Na_2CO_3$

$40g$ of $NaOH$ contains $6xx10^23$ molecules
$:.$ $30g$ of $NaOH$ contains $(30xx6xx10^23)/40$ molecules
$=4.5xx10^23$ molecules

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