A spherical object has a radius of 28.9 cm. If the density of the object is 3.52 g/cm^3, what is its mass?

By using , we can calculate the gravitational attraction as if the solid sphere were a point mass, with all the mass concentrated at the center of the sphere....

This is a basic algebraic equation. If the mass of each sweet is M and the mass of the basket is B, then you have two equations in two unknowns...

Your goal here will be to use two conversion factors, one to take you from grams to kilograms and one to take you from cubic centimeters to cubic meters....

$rho, "density" ="Mass"/"Volume"$. The object displaces a volume of $(50-30)*mL =20*mL$. Given that we know the mass the calculation of the density is now easy.

$"Density"$ $=$ $"Mass"/"Volume"$ Thus $"Mass"$ $=$ $"Density"(rho)xx"volume"$ $"Mass of silver"$ $=$ $10.5*g*cancel(cm^-3)xx5*cancel(cm^3)$ $=$ $52.5*g$. $"Mass of gold"$ $=$ $19.3*g*cancel(cm^-3)xx5*cancel(cm^3)$ $~=$ $100*g$. Note that I solved this problem dimensionally. I wanted...

Stokes' Law Stokes' law states that the settling velocity $v$ of small spheres in a fluid is given by $v = (gd^2(ρ_p - ρ_f))/(18eta)$ where $g$ = the gravitational...

The equation for : $rho = m/V$ Plug in known values, if your answer is in units of $(kg)/(m^3)$: $rho = (4kg)/(20m^3) = 0.2(kg)/(m^3)$ A more conventional unit for density...

The equation for : $rho = m/V$ Plug in known values, if your answer is in units of $(kg)/(m^3)$: $rho = (4kg)/(20m^3) = 0.2(kg)/(m^3)$ A more conventional unit for is...

We're asked to find the of the rock, given some mass and volume information. We're given that the mass of the system before the rock was added was...

If there are two an element $"Average atomic mass" = "mass"_axx "fract"_a + "mass"_b xx "fract"_b$ In the given problem about Hafnium, 5 isotopes have been given. Extending the...