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Hydrogen peroxide decomposes into water and oxygen gas. how many moles of hydrogen peroxide are needed to produce 1.5 mol of oxygen (balenced equation needed)
Moles of hydrogen peroxide needed=1.5 moles
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Ammonia is produced synthetically by the reaction below. How many moles of NH3 are formed when 200.0 g of N2 reacts with hydrogen?
3H2 + N2 = 2NH3 First, are looking for the amount of substanceof nitrogen: n(N2) = 200 g / 28 g/mol = 7.14 mol n(NH3) = n(N2) * 2 n(N2)...
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a. If 4.5 mol of ethane, C2H6, undergo combustion according to the unbalanced equation C2H6+O2---->CO2+H2O, how many moles of oxygen are required? b. How many moles of each product are formed?
If 4.5 mol of ethane, C2H6, undergo combustionaccording to the unbalanced equation the amount of O2 is the samethat amount of ethane. C2H6 + O2 ----gt; CO2 + H2O, so...
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If 2.00 moles of H2 and 1.55 moles of O2 react how many moles of H2O can be produced in the reaction below? 2H2+O2+2H2O
In this reaction O2 is the excess reactant and H2 is the limiting reactant, because:n(H2)/2 < n(O2)/1 ; 1<1.55;1 and 2 - stoichiometric coefficients of O2 and H2 respectively;That's why...
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How many moles of HCl could be formed from 5.48 moles of PCl3 and 7.44 moles of water in the following reaction?
PCl3 + 3H2O = 3HCl + H3PO3 water is in shortage, so : n(HCl) = 7.44 mol
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if 0.3 moles of H2O were produced how man moles of carbon dioxide would also have been produced
C2H6 + 7/2O2 -> 2CO2 + 3H2O
if 0.3 moles of H2O were produced how man moles of carbon dioxide would also have been producedC2H6 + 7/2O2 -> 2CO2 + 3H2OSolution:n(CO2)=2/3*n(H2O);n(CO2)=(2*0,3)/3=0,2 molAnswer:n(CO2)=0,2 mol.
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In the reaction 4Al(s)+3O2(g)-> Al2O3(s)
A. How many moles of oxygen react with 5.5 miles of Al?
B. How many moles of Al2O3 can be produced from 5.5 moles of Al?
A. 4,125B. 1,375
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How many moles of oxygen are produced when 756 grams of lead 11 oxide are formed
Find the mass of nitrogen dioxide that forms with 0.58 moles of oxygen
1) 2 Pb + O2 = 2 PbOthe amount of PbO is 756 g / 223.2 g/mole = 3.38 mole, it is twice of moles of O2, i.e.the amount of...
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If 7.0 moles of nh3 reacts with 14 moles of o2, how many moles of no2 will be produced?
Calculate how many moles of excess reactant will remain
4NH3 + 7O2 = 4NO2 + 6H2OAccording to the equation NH3 reacts completely, O2 is in the excess.7 mol of NO2 will be produced.According to the equation 7mol*7/4 = 12....
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A container filled with 0.534 moles of hydrogen has a volume of 34.0L. After using some hydrogen in an experiment, 0.150 moles of hydrogen remain. What is the new volume of the hydrogen?
0.534 moles of hydrogen contains 34.0 L volume0.150 moles of hydrogen contains = (34× 0.150)/0.534 L = 9.55 L (Answer)New volume of hydrogen is 9.55 L
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