HCl solution consists of 28% HCl by mass and has a density of 1.14g/ml. Find volume of the solution required to react with 1.87g Al as in the reaction: 2Al + 6HCl = 2AlCl3 + 3H2

2Al(s) + 3Cl2(g) → 2AlCl3 (aq) Aluminium is oxidized and is therefore the reducing agent. Chlorine is reduced and is therefore the oxidizing agent.

6 moles of HCl reacts with 2 moles of Al to gives 2 moles of AlCl3 and 3 moles of H2 2 moles of Al = 2× 13 = 26...

Mass of hydrogen formed by 25 gm Al = (1/9) × 25 gram = 2.78 gram.

2Al + 3Cl2 ==> 2AlCl3Find limiting reactant:moles Al present = 12.8 g Al x 1 mol Al/27.0 g = 0.474 moles Al (÷2 ->0.237)moles Cl2 present = 31.9 g Cl2...

P = 100 kPa T = 25oC + 273 = 298 KV = 500 mL = 0.5 LR = 8.314 kPa L K-1 mol-1Solution:The balanced chemical equation:6HCl(aq) + 2Al(s) =...

The reactant that produces a lesser amount of product is the limiting reagent.The reactant that produces a larger amount of product is the excess reagent.To find the amount of remaining...

n = m / MM (Al) = 27 g/molM (H2) = 2 g/moln (Al) = 30 / 27 = 1.1 molAccording to the equation, n (H2) = 3/2 x n...

67.2 x 2.5/54 =3.1 L

M(Al) = 26.98 g/mol;n=m/M;n(Al) = 1/26.98 = 0.037 moles;M(Cl2) = 70.90 g/mol;n(Cl2) = 1/70.90 = 0.014 moles;The mole ratio Al:Cl2 according to the reaction is 2:3;The mole ratio Al:Cl2 according...

The reaction rate can be determined by observing the rate of disappearance of the reactants (Al and HCl) and also by observing the rate of appearance of the products (AlCl3...