For the reaction shown, find the limiting reactant for each of the following initial amount of reactants. 2Al (s)+3Cl2 (g) —> 2AlCl3 (s) 1.0g Al; 1.0g Cl2

Md Ariful Islam

0 like 0 dislike
1 views
Share with your friends

1 Answers

Md Ariful Islam

Call

M(Al) = 26.98 g/mol;

n=m/M;

n(Al) = 1/26.98 = 0.037 moles;

M(Cl2) = 70.90 g/mol;

n(Cl2) = 1/70.90 = 0.014 moles;

The mole ratio Al:Cl2 according to the reaction is 2:3;

The mole ratio Al:Cl2 according to the initial amount of reactants is 0.037:0.014 or 2.6:1.

Answer: Cl2 is the limiting reactant. 

0 like 0 dislike
1 views
Talk Doctor Online in Bissoy App
When 2.5g of Al reacts with 5.0g of Cl2, 8.3g of AlCl3 is formed. Calculate the limiting reactants, theoretical yield, and percent yield for the reaction. 2Al + 3Cl3 ---> 2AlCl3

2Al + 3Cl2 ==> 2AlCl3Find limiting reactant:moles Al present = 12.8 g Al x 1 mol Al/27.0 g = 0.474 moles Al (÷2 ->0.237)moles Cl2 present = 31.9 g Cl2...

1 Answers 1 views
MnO2 + HCl = MnCl2 + Cl2 + H2O If 1.92 mol of MnO2 and 96.4g of HCl react, determine the limiting reagent. Also determine the mass of Cl2 and the mass of unused reactant after the reaction.

=23g of Chlorine will be produced.

1 Answers 1 views
For the reaction shown, find the limiting reactant for each of the following initial amounts of reactants. 2Al(s)+3Cl 2 (g)→2AlCl 3 (s)

Cl2 is the limiting reagent

1 Answers 1 views
In a chemical reaction, your limiting reactant was used up. You have a large quantity of excess reactant remaining. Will the reaction procees? Why or why not?

No, we don't have all reactants required for the reaction, so it wouldn't proceed.

1 Answers 1 views
HCl solution consists of 28% HCl by mass and has a density of 1.14g/ml. Find volume of the solution required to react with 1.87g Al as in the reaction: 2Al + 6HCl = 2AlCl3 + 3H2

2Al + 6HCl = 2AlCl3 + 3H2M (Al) = 26.98 g/mol2 x 26.98 reactsM (HCl) = 36.46 g/mol6 x 36.46 g reactsGiven mass of Al: 1.87 gThe ratio is:1.87 /...

1 Answers 1 views
What is the limiting reactant if you have 100 grams of NaOH and 100 grams of Al? 6NaOH + 2Al ---> 2Na3AlO3 + 3H2

In a chemical reaction, the limiting reagent, also known as the "limiting reactant", is the substance which is totally consumed when the chemical reaction is complete. The amount of product...

1 Answers 1 views
Based on the following equation: 6HCL(aq)+ 2AL(s)> 2ALCL3(aq) + 3H2 (g) What mass of aluminum is needed to produce 500 mL of hydrogen gas at 25 degrees Celcius and 100 kPa?

P = 100 kPa T = 25oC + 273 = 298 KV = 500 mL = 0.5 LR = 8.314 kPa L K-1 mol-1Solution:The balanced chemical equation:6HCl(aq) + 2Al(s) =...

1 Answers 1 views
What it the mass concentration of the excess reagent in the non Stoichemtric reaction (6HCl+2Al ➡2AlCl3+3H2)

The reactant that produces a lesser amount of product is the limiting reagent.The reactant that produces a larger amount of product is the excess reagent.To find the amount of remaining...

1 Answers 1 views
Calculate the grams of indicated product when 17.5 g of the first reactant and 10.1 g of the second reactant is used: Al2S3(s)+6H2O(l)→2Al(OH)3(aq)+3H2S(g)

Answer n(Al₂S₃)=m(Al₂S₃)/M(Al₂S₃)=1,75g/150g/Ml=0,012 Ml n(H₂O)=m(H₂O)/M(H₂O)=10,1g/18g/Ml=0,561Ml 1Mol Al₂S₃ : 6Mol H₂O for equation 0,012 Mol Al₂S₃ : 0,561 Mol H₂O Or 1 Mol Al₂S₃ : 46,75 Mol H₂O Al₂S₃ - shortcoming H₂O...

1 Answers 1 views
2al+3cl2=2alcl3 how many liters at stp of chlorine gas are needed to reaft woth 2.50 grams of aluminum

67.2 x 2.5/54 =3.1 L

1 Answers 1 views
X