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<h3 class="editor-header">Gizmos Moles Simulation</h3>
i) Understand the definition of a mole and determine the Avogadro constant by adding atoms or molecules to a balance until the mass in grams is equal to the atomic...
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Calculate the mass of hydrogen formed when 25 grams of aluminum reacts with excess hydrochloric acid. 2Al + 6HCl Al<sub>2</sub>Cl<sub>6</sub> + 3H<sub>2</sub>
Mass of hydrogen formed by 25 gm Al = (1/9) × 25 gram = 2.78 gram.
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How many moles of ammonia are produced when 0.60 moles of nitrogen reacts with hydrogen? N2(g) + 3H2(g) => 2NH3(g)
=1.2moles of Ammonia
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predict the mass of hydrogen gas produced when 2.73g of aluminum reacts in a single replacement reaction with excess sulphuric acid.
2Al+ 3H2SO4--> 3H2+Al2(SO4)3
For answering this question you need the next: Molecular weight of Al = 26.98 Molecular weight of H2 = 2.01 2.73g m 2Al + 3H2SO4--gt; 3H 2+Al2(SO4)3 2*26.98 3*2.01 m=...
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HCl solution consists of 28% HCl by mass and has a density of 1.14g/ml. Find volume of the solution required to react with 1.87g Al as in the reaction:
2Al + 6HCl = 2AlCl3 + 3H2
2Al + 6HCl = 2AlCl3 + 3H2M (Al) = 26.98 g/mol2 x 26.98 reactsM (HCl) = 36.46 g/mol6 x 36.46 g reactsGiven mass of Al: 1.87 gThe ratio is:1.87 /...
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what mass of hydrochloric acid reacts when 87.7 grams of aluminum dissolves in excess hydrochloric acid?
2Al + 6HCl = 2AlCl3 + 3H2 n = m/M M (Al) = 26.9 g/mol M (HCl) = 36.5 g/mol n (Al) = 87.7/26.9 = 3.3 mol n (HCl) =...
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Based on the following equation:
6HCL(aq)+ 2AL(s)> 2ALCL3(aq) + 3H2 (g)
What mass of aluminum is needed to produce 500 mL of hydrogen gas at 25 degrees Celcius and 100 kPa?
P = 100 kPa T = 25oC + 273 = 298 KV = 500 mL = 0.5 LR = 8.314 kPa L K-1 mol-1Solution:The balanced chemical equation:6HCl(aq) + 2Al(s) =...
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What it the mass concentration of the excess reagent in the non Stoichemtric reaction (6HCl+2Al ➡2AlCl3+3H2)
The reactant that produces a lesser amount of product is the limiting reagent.The reactant that produces a larger amount of product is the excess reagent.To find the amount of remaining...
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When aluminum reacts with hydrochloric acid, HCl, both aluminum chloride and hydrogen gas are produced. If 108 grams of aluminum is reacted, what volume of gas may be collected at STP?
Solution:Balanced chemical equation:2Al + 6HCl → 2AlCl3 + 3H2According to the equation above: n(Al)/2 = n(H2)/3The molar mass of Al is 27 g/mol.Hence,Moles of Al = (108 g Al) ×...
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Calculate the mass of hydrogen formed when 30 grams of aluminum reacts with excess hydrochloric acid according to the balanced equation below: 2Al + 6HCl --> 2AlCl<sub>3</sub> + 3H<sub>2</sub>
n = m / MM (Al) = 27 g/molM (H2) = 2 g/moln (Al) = 30 / 27 = 1.1 molAccording to the equation, n (H2) = 3/2 x n...
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