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<h3 class="editor-header">How Many Aluminum Reacts With Oxides Of Hydrochloric Acid For 3 Moles Of Hydrogen Gas2Al - 6HCl → 2AlCl3 3H2?</h3>
6 moles of HCl reacts with 2 moles of Al to gives 2 moles of AlCl3 and 3 moles of H2 2 moles of Al = 2× 13 = 26...
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7) Aluminum oxide is decomposed using electricity to produce aluminum metal. How many grams of aluminum metal can be produced from 100.0 g of Al2O3? 2Al2O3 -> 2Al + 3O2
Grams of Aluminum metal can be produced=52.92g
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Calculate the mass of hydrogen formed when 25 grams of aluminum reacts with excess hydrochloric acid. 2Al + 6HCl Al<sub>2</sub>Cl<sub>6</sub> + 3H<sub>2</sub>
Mass of hydrogen formed by 25 gm Al = (1/9) × 25 gram = 2.78 gram.
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When 2.5g of Al reacts with 5.0g of Cl2, 8.3g of AlCl3 is formed. Calculate the limiting reactants, theoretical yield, and percent yield for the reaction. 2Al + 3Cl3 ---> 2AlCl3
2Al + 3Cl2 ==> 2AlCl3Find limiting reactant:moles Al present = 12.8 g Al x 1 mol Al/27.0 g = 0.474 moles Al (÷2 ->0.237)moles Cl2 present = 31.9 g Cl2...
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For the reaction shown, find the limiting reactant for each of the following initial amounts of reactants. 2Al(s)+3Cl 2 (g)→2AlCl 3 (s)
Cl2 is the limiting reagent
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2Fe + 3Cl2 = 2FeCl3
This is an oxidation-reduction (redox) reaction:6 Cl0 + 6 e- → 6 Cl-I(reduction)2 Fe0 - 6 e- → 2 FeIII(oxidation)Cl2 is an oxidizing agent, Fe is a reducing agent.
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HCl solution consists of 28% HCl by mass and has a density of 1.14g/ml. Find volume of the solution required to react with 1.87g Al as in the reaction:
2Al + 6HCl = 2AlCl3 + 3H2
2Al + 6HCl = 2AlCl3 + 3H2M (Al) = 26.98 g/mol2 x 26.98 reactsM (HCl) = 36.46 g/mol6 x 36.46 g reactsGiven mass of Al: 1.87 gThe ratio is:1.87 /...
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Based on the following equation:
6HCL(aq)+ 2AL(s)> 2ALCL3(aq) + 3H2 (g)
What mass of aluminum is needed to produce 500 mL of hydrogen gas at 25 degrees Celcius and 100 kPa?
P = 100 kPa T = 25oC + 273 = 298 KV = 500 mL = 0.5 LR = 8.314 kPa L K-1 mol-1Solution:The balanced chemical equation:6HCl(aq) + 2Al(s) =...
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What it the mass concentration of the excess reagent in the non Stoichemtric reaction (6HCl+2Al ➡2AlCl3+3H2)
The reactant that produces a lesser amount of product is the limiting reagent.The reactant that produces a larger amount of product is the excess reagent.To find the amount of remaining...
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for CH4(g) + 3Cl2(g) ——> CHCl3(g) + 3HCl(g) how many grams of CH4 is needed to produce 45.5 g CHCl3
Solution:The molar mass of CH4 is 16.04 g/molThe molar mass of CHCl3 is 119.38 g/molCalculate the moles of CHCl3:(45.5 g CHCl3) × (1 mol CHCl3 / 119.38 g CHCl3) =...
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