P1V1 = P2V20.88 atm × 1.50L = 2.00L × X1.32 = 2.00XX = 1.32/2.00= 0.66 atm
1 Answers 1 viewsDalton's law states; The total pressure exerted by a mixture of gases is equal to the sum of the pressures of each of the different gases making up the mixture,...
1 Answers 1 viewsAccording to Dalton's Law of Partial Pressure;Pt= Px +Py+ Pz = (340+264+100)mmHg (since 1torr=1mmHg) = 704mmHg
1 Answers 1 viewsUsing the gas law: pV = nRT, and keeping the same number of moles of gas (n),we find the final volume V2:V2 = (T2/p2)*(p1*V1/T1) = (293 K/ 4.0 atm)*(2.0 atm...
1 Answers 1 views7g of nitrogen and excess of nitrogen will form excess of ammonia
1 Answers 1 viewsThe weight and size of the molecules that are negotiated in the ideal gas law increase the volume of the gas mixture. However, as the container has a constant volume,...
1 Answers 1 viewsSolution:Calculate the mole fraction (x) of O2 gas in the mixture:x(O2) = number moles of O2 / total number moles of gasTotal number moles of gas = Moles of...
1 Answers 1 viewsollowing the Ideal gas law: pV=nRT where R is gas constant and equal to 0.0821 L·atm·K-1·mol-1 For this case, pressure in atm have been equal to: p=nRTV=40.8 (mol)∙0.0821 (L∙atm∙K-1∙mol-1)∙298 (K)/...
1 Answers 1 viewsTo answer this question we should use ideal gas law : PV=nRT. V= 100mL=0.1 L = 0.1 dm3= 0.110-3m3; P= 688 mmHg or P =688133.322 Pa =91725.54 Pa; T =565C...
1 Answers 1 viewsIn one mole of nitrogen gas (N2) there are two atoms of nitrogen (N). There are six atoms of nitrogen(N) in three moles of nitrogen gas (N_2)
1 Answers 1 views