New temperature=156.5K
1 Answers 1 viewsOsmotic pressure =12.7atm
1 Answers 1 views5 atm — 25Cx atm — 32Cx=32*5/25=6.4 atm
1 Answers 1 views922×1.14×2.33/9.8731= 248.05J
1 Answers 1 viewsUsing the gas law: pV = nRT, and keeping the same number of moles of gas (n),we find the final volume V2:V2 = (T2/p2)*(p1*V1/T1) = (293 K/ 4.0 atm)*(2.0 atm...
1 Answers 1 viewsAt equillibrium temperature of water vapour is 100°cSo we have,, P1/T1=P2/T2=103170/100=99390/T2=T2=99390/1031.7=96.3 degrees.
1 Answers 1 viewsGiven n=MassMolar mass=PVRT.Mass=PVRT×molar mass,.........Agreed........?And, as is typical, we use the value of..........R=0.0821⋅L⋅atm⋅K−1⋅mol−1The which has units that chemists typically use. And so we plugs in the numbers:Mass=1.2⋅atm×2.00⋅L×4.00⋅g⋅mol−10.0821⋅L⋅atmK⋅mol×300⋅K≅400 moles
1 Answers 1 viewsAs we know, Total pressure is the sum of partial pressure of individual gases.PT = 1.05 -(0.08+0.05+Pair)Pair = [0.92] atm
1 Answers 1 viewsP1 = unknownV1 = 15 LP2 = 4.3 atmV2 = 8 LT1 = T2 = constSolution:Since the temperature and amount of gas remain unchanged, Boyle's law can be used. Boyle's gas law...
1 Answers 1 viewsAnswer on Question #83513Container A holds 782 mL of ideal gas at 2.80 atm. Container B holds 174 mL of ideal gas at 4.40 atm. If the gases are allowed...
1 Answers 1 views