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Ammonia is produced from its elements in a formation reaction. If 7.22 x 10<sup>24</sup> molecules of ammonia are produced, how many mole of ammonia was produced?
6.023×1023 molecules of ammonia = 1 mole ammonia7.81×1024 molecules of ammonia = (1×7.81×1024) / 6.023×1023 = 12.9612.96 moles of ammonia was produced.
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If 54.0 grams of water are mixed with excess magnesium nitride, How many grams of ammonia (NH₃) are produced? Mg₃N₂ + 6H₂O --> 2NH₃ + 3Mg(OH)₂
Grams of ammonia (NH₃) produced=17.0g
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When 40 grams of ammonium nitrate explode 14 grams of nitrogen and 8 grams of oxygen are formed. How many grams of water are formed?
You can calculate this by such reaction: NH₄NO₃ --gt; N₂ + frac12;O₂ + 2H₂O ==gt; 2NH₄NO₃ --gt; 2N₂ + O₂ + 4H₂O The law of conservation of mass solves this...
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calculate the mass of 2.4 moles of ammonia, NH3
answer: __grams
A student performing this reaction makes 8.5 grams of ammonia, NH3. How many moles of ammonia did she make?
answer:__moles
Solution:The molar mass of NH3 is 17.031 g/mol.Hence,a) Mole to Grams conversion:2.4 mol NH3 × (17.031 g NH3 / 1 mol NH3) = 40.8744 g NH3 = 40.87 g NH3Answer...
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According to the following reaction, how many grams of bromine monochloride will be formed upon the complete reaction of 26.6 grams of chlorine gas with excess bromine?
The equation for this reaction is: Br2 + Cl2 → 2BrCl The number of moles of chlorine gas equals: ν(Cl2) = m(Cl2)/Mr(Cl2) = 26.6 g / (2×35.5 g mol-1) =...
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How many grams of potassium phosphate will be formed upon the complete reaction of 30.7 grams of phosphoric acid with excess potassium hydroxide
H₃PO₄+3KOH=K₃PO₄+3H₂O 1MolH₃PO₄ -gt; 1Mol K₃PO₄ V(H₃PO₄)=m/M=30.7g/98g/Mol=0.313Mol V(K₃PO₄)=0.313Mol m(K₃PO₄)=V*M=0.313Mol*212g/Mol=66.36g
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Ammonia is produced from its elements in a formation reaction. If 7.81 x 1024 molecules of ammonia are produced, how many mole of ammonia was produced?
6.023×1023 molecules of ammonia = 1 mole ammonia7.81×1024 molecules of ammonia = (1×7.81×1024) / 6.023×1023 = 12.96 mole ammonia (Answer)12.96 mole of ammonia was produced.
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How many grams of sodium hydroxide will be formed upon the reaction of 27.9 grams of water with excess sodium?
Balanced equation2Na + 2H2O ---- 2NaOH + H22kmol H2O= 2kmolNaOH2molH2O= 2 mol NaOH2(18gm H2O) = 2(40 gm NaOH)18 gm H2O = 40 gm NaOH gmofNaOH produced = 40/18 *27.9 gm...
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Ammonia is produced from its elements in a formation reaction. If 7.19 x 10<sup>24</sup> molecules of ammonia are produced, how many mole of ammonia was produced?
Given,Number of molicule of amomonia produce = 7.19 x 1024 molecules We know, 6.023 x 1023 molicule = 1 mole 1 molicule = (1/(6.023x1023)) mole 7.19 x 1024 molecules...
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when nitrogen gas reacts with hydrogen gas,ammonia gas is formed.How many grams of hydrogen gas are required to react completely with 3,5 L of nitrogen at STP?
Solution:A chemical equation must be balanced:N2 + 3H2 = 2NH3According to the reaction equation for 3 mol of H2 is needed 1 moles of N2.Therefore, mass of H2 = V...
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