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When 40 grams of ammonium nitrate explode 14 grams of nitrogen and 8 grams of oxygen are formed. How many grams of water are formed?
You can calculate this by such reaction: NH₄NO₃ --gt; N₂ + frac12;O₂ + 2H₂O ==gt; 2NH₄NO₃ --gt; 2N₂ + O₂ + 4H₂O The law of conservation of mass solves this...
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If 86.33 grams of sodium reacts with an excess of chlorine, what amount of Salt (sodium chloride) will be produced? Sodium + chlorine ® sodium chloride Na + Cl2 ® NaCl
Solution:Sodium + chlorine → sodium chloride The balanced chemical equation:2Na + Cl2 → 2NaClAccording to the equation above: n(Na) = n(NaCl)Moles of Na = Mass of Na / Molar mass of NaThe molar...
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If you start with 25.0 grams of lead (II) nitrate and 15.0 grams of sodium iodide, how many grams of sodium nitrate can be formed?
Pb(NO3)2 + 2NaI = 2NaNO3 + PbI2n = m / MM (Pb(NO3)2) = 331.2 g/molM (NaI) = 150 g/molM (NaNO3) = 85 g/moln (Pb(NO3)2) = 25 / 331.2 = 0.08...
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According to the following reaction, how many grams of bromine monochloride will be formed upon the complete reaction of 26.6 grams of chlorine gas with excess bromine?
The equation for this reaction is: Br2 + Cl2 → 2BrCl The number of moles of chlorine gas equals: ν(Cl2) = m(Cl2)/Mr(Cl2) = 26.6 g / (2×35.5 g mol-1) =...
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How many grams of potassium phosphate will be formed upon the complete reaction of 30.7 grams of phosphoric acid with excess potassium hydroxide
H₃PO₄+3KOH=K₃PO₄+3H₂O 1MolH₃PO₄ -gt; 1Mol K₃PO₄ V(H₃PO₄)=m/M=30.7g/98g/Mol=0.313Mol V(K₃PO₄)=0.313Mol m(K₃PO₄)=V*M=0.313Mol*212g/Mol=66.36g
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2NaOH+H2SO4 - 2H2O+Na2SO4
how many grams of sodium sulfate will be formed if you start with 250 grams of sodium hydroxide and you have an excess of sulfuric acid?
First we must calculate the mole for NaOH. n(NaOH)=250/40= 6.25 moles of NaOH. From reaction we see than 2 moles of NaOH give 1 mole of Na2SO4. That means, that...
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Sodium reacts with water to produce hydrogen gas and sodium hydroxide. How many grams of H2(g) are produced when 5.0 g Na reacts with 100.0 g of water?
0.2 g
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If you need a 2.5M solution of sodium hydroxide, what mass of sodium hydroxide must be dissolved in 600 mL of water?
M(NaOH) = 39.997 g/mol;Proportion:2.5 moles – 1000 mLx moles – 600 mLx = 1.5 moles;m = n×M;m(NaOH) = 1.5 moles × 39.997 g/mol = 59.995 gAnswer: 60 g
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how many grams of water can be formed when 80 grams of sodium hydroxide reacts with an excess of sulfuric acid in solution?
H2SO4 + 2NaOH --> Na2SO4 +2 H2Ois the balanced equationmols of NaOH present = 80 g/40 g/mol = 2 molsAccording to balanced equation 2 mol NaOH yield 2 mol waterMass...
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What is the molarity of 50ml solution of sodium hydroxide from 2.0114 g of sodium hydroxide and water.
Molar mass of sodium hydroxide = 40 g no. Of moles of NaOH = 2.0114/40 = 0.050285 moles Molarity = no. Of moles / volume Molarity = 0.050285/50Molarity = 0.0010057...
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