According to the following reaction, how many grams of bromine monochloride will be formed upon the complete reaction of 26.6 grams of chlorine gas with excess bromine?

7g of nitrogen and excess of nitrogen will form excess of ammonia

You can calculate this by such reaction: NH₄NO₃ --gt; N₂ + frac12;O₂ + 2H₂O ==gt; 2NH₄NO₃ --gt; 2N₂ + O₂ + 4H₂O The law of conservation of mass solves this...

Solution:Sodium + chlorine → sodium chloride  The balanced chemical equation:2Na + Cl2 → 2NaClAccording to the equation above: n(Na) = n(NaCl)Moles of Na = Mass of Na / Molar mass of NaThe molar...

Solution:The balanced chemical equation:2KBr + Cl2 → 2KCl + Br2According to the equation above: n(Br2) = n(KBr)/2Moles of KBr = Mass of KBr / Molar mass of KBrThe molar mass of...

H₃PO₄+3KOH=K₃PO₄+3H₂O 1MolH₃PO₄ -gt; 1Mol K₃PO₄ V(H₃PO₄)=m/M=30.7g/98g/Mol=0.313Mol V(K₃PO₄)=0.313Mol m(K₃PO₄)=V*M=0.313Mol*212g/Mol=66.36g

A sample of chlorine gas at 543 Torr has a volume of 21.6 L. If the temperature of the chlorine is 0°C, how many moles of chlorine gas are present?...

48.9 g of aluminium chloride is formed1.07 moles of aluminium is excess.

m = V×ρm(Br2) = 8.50 mL × 2.91 g/mL = 24.735 gM(Br2) = 159.808 g/moln = m/Mn(Br2) = 24.735 g / 159.808 (g/mol) = 0.154 molOne mole of Br2 molecules...

At first, kilogrammes should be turned into grams:m=80×1000=80000(g).Then, mass should be divided by molar mass:n=m/M=80000/79.9=1001.3(mol).(The data is not very clear. If the point is not mistake, and there are .80...

Balanced equation2Na + 2H2O ---- 2NaOH + H22kmol H2O= 2kmolNaOH2molH2O= 2 mol NaOH2(18gm H2O) = 2(40 gm NaOH)18 gm H2O = 40 gm NaOH gmofNaOH produced = 40/18 *27.9 gm...