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What is the initial pressure of a gas having an initial temperature of 90.5K, an initial volume of 40.3 L, final pressure of .83 atm, a final temperature of .54 K and a final volume of 2.7L?

Md Ariful Islam

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1 Answers

Md Ariful Islam

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Use the . $(P_1V_1)/T_1=(P_2V_2)/T_2$

Given
$V_1="40.3 L"$
$T_1="90.5 K"$
$P_2="0.83 atm"$
$V_2="2.7 L"$
$T_2="0.54 K"$

Unknown
$P_1$

Equation
$(P_1V_1)/T_1=(P_2V_2)/T_2$

Solution
Rearrange the equation to isolate $P_1$ and solve.

$P_1=(P_2V_2T_1)/(T_2V_1)$

$P_1=((0.83"atm" xx2.7cancel"L"xx90.5cancel"K"))/((0.54cancel"K"xx40.3cancel"L"))="9.3 atm"$

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