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You have a sample of neon gas at a certain pressure, volume, and temperature. You double the volume, double the number of moles of neon, and double the Kelvin temperature. How does the final pressure (Pf) compare to the original pressure (Po) ?
The final pressure will double as well. If you use the equation, $PV = nRT$, to express the initial and the final states of your gas sample, you can...
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A gas is held at 3.8 atm and 500 K. If the pressure is then decreased to 1.2 atm, what will the new temperature be?
This question involves Gay-Lussac's law to answer, which states that the pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature. This...
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A gas is held at 3.8 atm and 500 K. If the pressure is then decreased to 1.2 atm, what will the new temperature be?
By changing the physical conditions like pressure, temperature and volume of the gas, the moles of the gas remain constant. $ n_1=n_2$ According to the ideal gas equation, $(P_1V_1)/(RT_1) =...
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What is the initial pressure of a gas having an initial temperature of 90.5 K, an initial volume of 40.3 L, a final pressure of 0.83 atm, a final temperature of 0.54 K and a final volume of 2.7 L?
$PV = nRT$ $(PV)/T = nR$ $therefore (P_1V_1)/T_1 = (P_2V_2)/T_2$, the . $(P_1*"40.3 L")/("90.5 K")=("0.83 atm"*"2.7 L")/("0.54 K")$ $P_1 approx 9.3atm$
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A 93mL sample of dry air cools from 144°C to -22°C while the pressure is maintained at 2.85 atm. What is the final volume?
This is an example of , which states that the volume of a given amount of gas held at constant pressure is directly proportional to the Kelvin temperature . This...
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A gas takes up a volume of 17.5 liters, has a pressure of 2.31 atm, and a temperature of 299 K. lf the temperature is increased to 350 K and the pressure is decreased to 1.75 atm, what is the new volume of the gas?
And so.................. $V_2=(P_1xxV_1xxT_2)/(T_1xxP_2)$ $=(2.31*atmxx17.5*Lxx350*K)/(299*Kxx1.75*atm)<=30*L.$
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What is the initial pressure of a gas having an initial temperature of 90.5K, an initial volume of 40.3 L, final pressure of .83 atm, a final temperature of .54 K and a final volume of 2.7L?
Use the . $(P_1V_1)/T_1=(P_2V_2)/T_2$ Given $V_1="40.3 L"$ $T_1="90.5 K"$ $P_2="0.83 atm"$ $V_2="2.7 L"$ $T_2="0.54 K"$ Unknown $P_1$ Equation $(P_1V_1)/T_1=(P_2V_2)/T_2$ Solution Rearrange the equation to isolate $P_1$ and solve. $P_1=(P_2V_2T_1)/(T_2V_1)$ $P_1=((0.83"atm"...
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A 3.00 liter sample of gas is at 288 K and 1.00 atm. If the pressure of the gas is increased to 2.00 atm and its volume is decreased to 1.50 liters, what will be the Kelvin temperature of the sample?
When you are given this much information in the context of a generic, unnamed gas, it's a good idea to consider the : $PV = nRT$ Before we...
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The pressure of 4.2 L of nitrogen gas in a flexible container is decreased to one-half its original pressure, and its absolute temperature is increased to double the original temperature. What is its volume now?
Your tool of choice for this problem will be the equation, which looks like this $color(blue)((P_1V_1)/T_1 = (P_2V_2)/T_2)" "$, where $P_1$, $V_1$, $T_1$ - the pressure, volume, and...
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Fifty liters of gas is kept at a temperature of 200 K and under pressure of 15 atm. The temperature of the gas is increased to 400 K. The pressure is decreased to 7.5 atm. What is the resulting volume of the gas?
Even without doing any calculations, you should be able to look at the information given and predict that the volume of the gas will increase after temperature is increased and...
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