Lithium and nitrogen react to produce lithium nitride: $6Li(s) + N_2(g) -> 2Li_3N(s)$. How many moles of lithium nitride are produced when 0.710 mol of lithium react in this fashion?

Md Ariful Islam

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Md Ariful Islam

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Since the given information is in moles, we need only look at the ratio between the chemicals:

Six moles of Li will produce 2 moles of lithium nitride. So, the ratio is 6:2 or 3:1.

Therefore, we can set up a proportion:

$(Li)/(Li_3N) = 3/1 = 0.710/x$

This tells us that in the general case, we need three times as much Li as the amount of $Li_3N$ to be produced, and that the amount of $Li_3N$ produced in this case must be in the same ratio. so, we can solve

$3/1 = 0.710/x$

Cross-multiply

$3x = 0.710$

$x= 0.710 -: 3 = 0.237$ mol of $Li_3N$ produced

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