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your equation works. However, it is better to use the smallest possible coefficients. Divide your by 2. It still works.

Start by using the 5 carbons in the hydrocarbon to form 5 carbon dioxide. Then use the 12 hydrogens to form 6 waters. Then count up the oxygen atoms needed.

$ 5 xx O_2 = 10 O$
$ 6 xx O_1 = 6 O$
= $ 16 O$
There must be 16 oxygens on the left or reactants to balance the equation. So

$ 8 xx O_2 = 16 O$

so

$ 1 xx C_5H_12 + 8 xx O_2 = 5 xx CO_2 + 6 xx H_2O$

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