You can double the equation if you like; either equation shows that 1 equiv of ethane reacts with 7/2 equiv dioxygen gas to give 2 equiv carbon dioxide and 3 equiv of water.
How does energy transfer in the reaction. Is it exothermic or endothermic?
The modern chemical bond is conceived to be a region of high electron between 2 positively charged atomic nuclei, such that internuclear is repulsion is negated, and a net attractive...
When a $3.0*g$ mass of carbon is burnt in an $8.0*g$ mass of dioxygen, the carbon and the oxygen are stoichiometrically equivalent. Of course, the combustion reaction proceeds according to...
This is a combustion reaction of an alkane with oxygen. It is exothermic ($DeltaH<0$), and can be balanced in normal methods for ie ensuring that the total number of atoms...
So two questions: is mass balanced?; is charge balanced? If you like you can double the equation to eliminate the half-integral coefficient; the mass transfer, the is still the same....
your equation works. However, it is better to use the smallest possible coefficients. Divide your by 2. It still works. Start by using the 5 carbons in the hydrocarbon...
The balanced equation of the combustion of ethane is: $2C_2H_6+7O_2->4CO_2+6H_2O$ Then number of mole of oxygen that will be needed to completely react with $5.49mol$ of ethane could be calculated...
The key here is to focus solely on the reaction that produces chloroethane, $"C"_2"H"_5"Cl"$, and ignore the one that produces dichloroethane, $"C"_2"H"_4"Cl"$, the side product of the reaction. Start by...
The first thing to do here is make sure that you have a balanced chemical equation. The equation given to you is actually unbalanced, so focus on writing a balanced...
Ethene undergoes incomplete combustion to form carbon dioxide, carbon monoxide and water vapour. The balanced equation of this incomplete combustion reaction is as follows. $C_2H_4(g)+5/2O_2(g)->CO_2(g)+CO(g)+2H_2O(g)$ But as per question the...
$"8.855 g/L"$ This is just asking you to calculate the new molar (i.e. molar solubility) at a different pressure, i.e. use the . (We'll end up converting...
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