When a $3.0*g$ mass of carbon is burnt in an $8.0*g$ mass of dioxygen, the carbon and the oxygen are stoichiometrically equivalent. Of course, the combustion reaction proceeds according to...
1 Answers 1 viewsHere is the balanced equation: $C_6H_12O_6 + 6O_2 rarr 6 CO_2 + 6 H_2O$ Since the molar mass of glucose is 180 g, the 45 g given mass in this...
1 Answers 1 viewsThe mass of glucose required is 30 g. Step 1. Start with the balanced equation $M_text(r):color(white)(ml) 180.16color(white)(mmmmmmmmmml)44.01$ $color(white)(mmm)"C"_6"H"_12"O"_6 + "6O"_2 → "6CO"_2 + 6"H"_2"O""$ Step 2. Calculate the...
1 Answers 1 viewsWe need a stoichiometic equation: $SO_2(g) + 1/2O_2(g) rarr SO_3(g)$ The equation unequivocally tells us that the reaction of $64*g$ $SO_2(g)$ with $16*g$ $O_2(g)$ gives $80*g$ $SO_3(g)$. The given masses...
1 Answers 1 viewsFirst, find the balanced chemical formula: $C_6H_12O_6 + 6O_2 rarr 6CO_2 + 6H_2O$ Since glucose forms carbon dioxide in a 1:6 ratio, we know that one mole of glucose yields...
1 Answers 1 viewsGiven: Mass of $"O"_2$; chemical equation (understood) Find: Moles of $"CO"_2$ Strategy: The central part of any problem is to convert moles of something to moles of something else....
1 Answers 1 viewsAt constant pressure and temperature, the volume of a gas represents the number of particles. You have given te stoichiometric equation: $2C-=O(g) + O_2(g) rarr 2CO_2(g)$, And this equation...
1 Answers 1 viewsEthene undergoes incomplete combustion to form carbon dioxide, carbon monoxide and water vapour. The balanced equation of this incomplete combustion reaction is as follows. $C_2H_4(g)+5/2O_2(g)->CO_2(g)+CO(g)+2H_2O(g)$ But as per question the...
1 Answers 1 viewsOld $"Dalton's Law of partial pressures"$ tells us that in a gaseous mixture, the exerted by a component gas is the same as the pressure it would exert if it...
1 Answers 1 views$"8.855 g/L"$ This is just asking you to calculate the new molar (i.e. molar solubility) at a different pressure, i.e. use the . (We'll end up converting...
1 Answers 1 views