The question states the compound is made up of only carbon, oxygen and hydrogen, therefore it narrows it down to Lipids or carbohydrates as a macromolecule choice.
Carbohydrates have a ratio of 2 hydrogen atoms for each oxygen and carbon atom.
Lipids do not have a set ratio like carbohydrates do.
This is called the of the element. To make it up to 13 in carbon-13, you will need 7 neutrons. Stable isotopes are not useful at all in radio-dating,...
1 Answers 1 viewsOr $"ferric oxide............"$ See this The link is public.
1 Answers 1 viewsTwo lone pair on the central and two species bonded to the central atom in the species would constitute tetrahedral electronic structure and bent , with bond angles less than...
1 Answers 1 viewsThe stoichiometrically balanced equation tells us unequivocally that $1$ $mol$ dihydrogen reacts with $0.50$ $mol$ dioxygen to give $1$ $mol$ water. $"Moles of dihydrogen"$ $=$ $(58.1*g)/(2.02*g*mol)$ $=$ $28.7*mol$ $H_2$ $"Moles...
1 Answers 1 viewsWe know that $1*mol$ contains $6.022xx10^23$ individual sodium atoms, and has a mass of $22.99*g$. And thus for $1.$ there is a $2*g$ mass of $Na$. For $2.$ there is...
1 Answers 1 viewsSee for details of its chemistry. It would be found in every inorganic and organic laboratory. It is used in the . The alternative representation is $""^(-)O-P^(+)Cl_3$; you will see...
1 Answers 1 viewsTrying to present a possible Answer We know that the molar mass of carbon and hydrogen are $C=12"g/mol" and H = 1"g/mol"$ When Carbon Hydrogen mass ratio is 11.89 The...
1 Answers 1 viewsThe idea here is that you can use the to figure out how much carbon and hydrogen you had in your $"2.500 g"$ sample of vanillin. When vanillin...
1 Answers 1 views$"Moles of chlorine"=(16.7*g)/(35.45*g*mol^-1)=0.47*mol$ $"Moles of sodium"=(10.8*g)/(22.99*g*mol^-1)=0.47*mol$ $"Moles of oxygen"=(22.5*g)/(16.00*g*mol^-1)=1.41*mol$ We divide thru by the smallest quantity, that of sodium, to give an empirical formula.....of $NaClO_3$, i.e. $"sodium chlorate"$.
1 Answers 1 viewsWe have been given an empirical formula of $C_4H_6O$. We know that the molecular formula is always a whole number multiple of the empirical formula. Thus ${4xx12.01+6xx1.01+16.0}xxn=280*g*mol^-1$. My arithmetic gives...
1 Answers 1 views