Chlorine reacts with hot sodium hydroxide solution. A sample of a compound formed in the reaction was found to contain 10.8 g of sodium atoms, 16.7 g of chlorine atoms and 22.5 g of oxygen atoms. What is the empirical formula of the compound formed?

Md Ariful Islam

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$"Moles of chlorine"=(16.7*g)/(35.45*g*mol^-1)=0.47*mol$

$"Moles of sodium"=(10.8*g)/(22.99*g*mol^-1)=0.47*mol$

$"Moles of oxygen"=(22.5*g)/(16.00*g*mol^-1)=1.41*mol$

We divide thru by the smallest quantity, that of sodium, to give an empirical formula.....of $NaClO_3$, i.e. $"sodium chlorate"$.

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