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$"Moles of sodium"$ $=$ $(0.92*g)/(22.99*g*mol^-1)=0.0400*mol$

$"Moles of chlorine"$ $=$ $(1.42*g)/(35.45*g*mol^-1)=0.0400*mol$.

$"Moles of oxygen"$ $=$ $(2.56*g)/(15.99*g*mol^-1)=0.160*mol$.

Note that I DIVIDED THRU BY the of each constituent. And now, we divide thru by the SMALLEST molar quantity, that of sodium, to get an empirical formula of $NaClO_4$; and this is $"sodium perchlorate"$,

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