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Trying to present a possible Answer

We know that the molar mass of carbon and hydrogen are

$C=12"g/mol" and H = 1"g/mol"$

When Carbon Hydrogen mass ratio is 11.89

The ratio of no. Of atoms of C and H is given by

$C/H=(11.89/12)/(1/1)~~1/1$

So empirical formula $CH->"possible"$

Now from the list

a)
When Carbon Hydrogen mass ratio is 2.5

The ratio of no. Of atoms of C and H is given by

$C/H=(2.5/12)/(1/1)~~5/24$

So empirical formula $C_5H_24->" not possible"$
Beceause the molecular formula of alkane with 5 C-atoms in the molecule is $C_5H_12$. So the maximum number of hydrogen with 5 C should not exceed 12.

b)
When Carbon Hydrogen mass ratio is 3.97

The ratio of no. Of atoms of C and H is given by

$C/H=(3.97/12)/(1/1)~~1/3$

So empirical formula $CH_3->"possible"$ This is found in ethane having MF $C_2H_6$

c)
When Carbon Hydrogen mass ratio is 4.66

The ratio of no. Of atoms of C and H is given by

$C/H=(4.66/12)/(1/1)~~7/18$

So empirical formula $C_7H_18->"not possible"$ Since maximum number of H with 7C-atoms is $7xx2+2=16$.So it has been exceeded.

d)
When Carbon Hydrogen mass ratio is 7.89

The ratio of no. Of atoms of C and H is given by

$C/H=(7.89/12)/(1/1)~~2/3$

So empirical formula $C_2H_3->" possible"$
Since the molecular formula of butyne or butadiene $C_4H_6$ supports the empirical formula
$ C_2H_3$