The main reason the noble gases do not need to bond with other is that their outermost subshells are filled. These are known as . Take helium for example. It...
1 Answers 1 viewsAnd the chalcogens........Group 16, and of course hydrogen.... Most elemental gases, save for the Noble Gases, are DIATOMIC. Lithium, beryllium, and carbon, form diatomic molecules that have spectroscopically observed.
1 Answers 1 viewsThe average of an element is calculated by taking the weighted average of the atomic masses of its stable . In other words, each stable isotope will contribute to...
1 Answers 1 viewsWhere the $delta$ symbol denotes a little bit of (or partial) positive or negative charge. Dipoles are drawn from positive to negative. The overall dipole moment is the vector sum...
1 Answers 1 viewsThe bond energy, or bond , expresses the energy needed to break a chemical bond, that's why it will always be listed as a positive value. In your case, 243...
1 Answers 1 viewsEvery molecule that consists of two atoms is diatomic. Only if the two atoms are the same there is a diatomic element. So $O_2$ is a diatomic element (and thus...
1 Answers 1 viewsFor , the atoms are rearranged so that an element replaces an element in the compound. It usually looks somewhat like this: $AB+C -> AC+B$
1 Answers 1 views$"Mass of 1 atom" = 1 color(red)(cancel(color(black)("atom"))) × "3000 u"/(50 color(red)(cancel(color(black)("atoms")))) = "60.0 u"$ $"Mass of 1 mol of atoms = 60.0 g"$ $"Number of moles" = 240 color(red)(cancel(color(black)("g"))) ×...
1 Answers 1 viewsWe know that $1*mol$ contains $6.022xx10^23$ individual sodium atoms, and has a mass of $22.99*g$. And thus for $1.$ there is a $2*g$ mass of $Na$. For $2.$ there is...
1 Answers 1 views$%A$ $=$ $(34.5*g)/(34.5*g+18.2*g+2.6*g)xx100%=62.3%$ $%B$ $=$ $(18.2*g)/(34.5*g+18.2*g+2.6*g)xx100%=33.0%$ $%C$ $=$ $(2.6*g)/(34.5*g+18.2*g+2.6*g)xx100%=4.70%$ That is $%" element"$ $=$ $"Mass of element"/"Mass of compound"xx100%$ $"Mass of compound"$ is clearly the SUM of the constituent ....
1 Answers 1 views