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First, we need to find the mass of $"Kr"$ by using the equation:

$m/M_r=n$, where:

  • $m$ = mass ($g$)
  • $M_r$ = molar mass ($gcolor(white)(l)mol^-1$)
  • $n$ = number of moles ($mol$)

$m=nM_r$

$m("Kr")=n("Kr")M_r("Kr")=0.176*83.8=14.7488g$

$rho=m/V=14.7488/8=1.8436~~1.84gcolor(white)(l)L^-1$

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