You have 48.3g of solid lithium sulfate. If it has a density of $"2220 g/L"$, what volume will this solid occupy?

Md Ariful Islam

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The problem tells you that lithium sulfate has a of $color(blue)("2220 g")$ $color(purple)("L"^(-1))$, which means that every $color(purple)("1 L")$ of lithium sulfate has a mass of $color(blue)("2220 g")$.

In your case, you know that the mass of an unknown volume of lithium sulfate is equal $"48.3 g"$, so use the density of the compound as a conversion factor to find the volume of the sample.

$48.3 color(red)(cancel(color(black)("g"))) * overbrace(color(purple)("1 L")/(color(blue)(2220)color(red)(cancel(color(blue)("g")))))^("given by the density of lithium sulfate") = color(darkgreen)(ul(color(black)("0.0218 L")))$

The answer is rounded to three , the number of you have for your values.

If you want, you can convert this to milliliters by using the fact that

$"1 L" = 10^3$ $"mL"$

You should end up with a volume of $"21.8 mL"$.

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