Call

Start with the equation for the reaction:

$2 "LiOH"+"CO"_2 \rightarrow "Li"_2"CO"_3+"H"_2"O"$

So one mole of lithium hydroxide reacts with one-half mole of carbon dioxide.

By adding up atomic masses we find that one mole of lithium hydroxide weighs about $23.9$ grams and one mole of carbon dioxidecweighs about $44.0$ grams.

So the ratio of lithium hydroxide to the carbon dioxide it reacts with is $23.9$ grams of lithium hydroxide to $22.0$ grams of carbon dioxide. Then $1.00$ kg $=1.00×10^3$ grams of lithium will react with:

$1.00×10^3"g LiOH"×(22.0 "g CO"_2)/(23.9 "g LiOH")=9.21×10^2"g CO"_2$

Talk Doctor Online in Bissoy App