From above,
For the volume with a mass of
For a given substance, its tells you the mass occupied by one unit of volume of that substance. In essence, is a measure of how well the molecules of...
1 Answers 1 views$"Density"$ $=$ $"Mass"/"Volume"$ by definition. Now this is the of the copper coin, not copper. In the UK copper coins, the $1$ $p$ and $2$ $p$ coins are copper plated...
1 Answers 1 viewsAlright so we know the formula for is $rho=m/v$ => where $rho$ is the density with units of the derived components, $m$ is the mass, and $v$ is the volume....
1 Answers 1 viewsThe problem tells you that lithium sulfate has a of $color(blue)("2220 g")$ $color(purple)("L"^(-1))$, which means that every $color(purple)("1 L")$ of lithium sulfate has a mass of $color(blue)("2220 g")$. In your...
1 Answers 1 viewsDo you agree? The copper displaces the given volume of water. Now $rho_"Cu"=8.90*g*cm^3$ OR $rho_"Cu"=8.90*g*mL^-1$, i.e. $1*mL-=1*cm^3$ But by definition, $rho_"density"="mass"/"volume"$ And thus $"mass"=rhoxx"volume"=8.90*g*cancel(mL^-1)xx23.4*cancel(mL)$ $=208.3*g$. Do you follow?
1 Answers 1 viewsYou have given the stoichiometric equation that represents reduction of cuprous sulfide: $Cu_2S(s) + O_2(g) rarr 2Cu(s) + SO_2(g)$ Sulfur is oxidized; copper and oxygen are reduced. $"Moles of copper"=(650*g)/(63.55*g*mol^-1)=10.3*mol$....
1 Answers 1 views$CuCO_3(s) + 2HCl(aq)rarrCuCl_2(aq) + CO_2(g)uarr + H_2O(l)$ Or........... $CuO(s) + 2HCl(aq)rarrCuCl_2(aq) + H_2O(l)$ For each acid base reaction the product is the beautiful blue-coloured $[Cu(OH_2)_6]^(2+)$ ion, which is commonly represented...
1 Answers 1 viewsThere is a loss of 0.4 grams. $ 2.0 -1.6$ = 0.4 grams $ 0.4/2.0 xx 100 $ = 20% The Hydrogen will combine with the Oxygen in...
1 Answers 1 viewsThe idea here is that you need to use the mass of copper and the mass of the copper sulfide to determine how much sulfur the produced compound contains, then...
1 Answers 1 viewsThe empirical formulas are $"Cu"_2"O"$ and $"CuO"$. Oxide 1 $color(white)(mmmmml)"Cu" +color(white)(m) "O" → "Oxide 1"$ $"Mass/g":color(white)(l) 2.118color(white)(ll) 0.2666$ Our job is to calculate the ratio of the moles of...
1 Answers 1 views