Sickle cell anemia is caused by a recessive allele. Roughly 1 out of every 500 african americans is afflicted with sickle cell anemia. How would you use the hardy weinberg equation to calculate the % of heterozygotes for sickle cell allele (.002=q^2)?

A question could look like: If $mathbf98$ out of $mathbf200$ individuals in a population express the recessive phenotype, what percent of the population would you predict would be heterozygotes?...

The Hardy-Weinberg principle states that in a large randomly breeding population, the frequency of alleles will remain the same from generation to generation, as long as certain assumptions are met....

The Hardy-Weinberg equilibrium assumes the following characteristics: organisms are diploid. only occurs. generations are non overlapping. mating is random. population size is infinitely large. allele frequencies are equal in...

If p is 0.23 then q should be 1 minus 0.23, i.e. 0.77.

When the number of individuals are already mentioned derive the frequency in 100 individuals: for this question which will be as following -- Number of homozygous dominant 49% ( $B^2$)...

Hardy Weinberg law gives the idea when there is no evolution or we can say that population remains in equilibrium. P + Q = 1 $P^2$ + 2PQ +...

Hardy Weinberg principle is variously known as HW law/theorem. Population geneticists term it as HW equilibrium. According to this, the frequencies of different alleles of a gene will remain constant...

The Hardy-Weinberg principle states that both allele and genotype frequencies will remain the same in successive generations of a growing population if (i) mating is random; (ii) no occur; (iii)...

For the first part of your question read this and the other links that the answer provides. And the following will give you an idea about the practical use...

Let's start with the basic Hardy-Weinberg equations first. $p+q=1$ and $p^2+2pq+q^2=1$ With "p" being the dominant allele and "q" being the recessive allele We know that 16% (or 0.16) show...