A question could look like: If $mathbf98$ out of $mathbf200$ individuals in a population express the recessive phenotype, what percent of the population would you predict would be heterozygotes?...
1 Answers 1 viewsThe Hardy-Weinberg principle states that in a large randomly breeding population, the frequency of alleles will remain the same from generation to generation, as long as certain assumptions are met....
1 Answers 1 viewsThe Hardy-Weinberg equilibrium assumes the following characteristics: organisms are diploid. only occurs. generations are non overlapping. mating is random. population size is infinitely large. allele frequencies are equal in...
1 Answers 1 viewsIf p is 0.23 then q should be 1 minus 0.23, i.e. 0.77.
1 Answers 1 viewsIn the Hardy-Weinberg equilibrium equation ($p^2 + 2pq + q^2 = 1$), the term $2pq$ represents the genotype frequency of heterozygotes (Aa) in a population in equilibrium. The term $p^2$...
1 Answers 1 viewsThe Hardy-Weinberg equation is: $p^2 + 2pq + q^2 = 1" "$ and also $" "p+q=1$ where $p^2$ is the percentage of homozygous dominant phenotype where...
1 Answers 1 viewsHardy Weinberg law gives the idea when there is no evolution or we can say that population remains in equilibrium. P + Q = 1 $P^2$ + 2PQ +...
1 Answers 1 viewsHardy Weinberg principle is variously known as HW law/theorem. Population geneticists term it as HW equilibrium. According to this, the frequencies of different alleles of a gene will remain constant...
1 Answers 1 viewsThe Hardy-Weinberg principle states that both allele and genotype frequencies will remain the same in successive generations of a growing population if (i) mating is random; (ii) no occur; (iii)...
1 Answers 1 viewsThe is $p^2+2pq+q^2=1$ where $p$ is the frequency of allele A $q$ is the frequency of allele a $p^2$ is the frequency of individuals with AA $2pq$ is the frequency...
1 Answers 1 views